<span>The water soaks in the cracks of rocks, freezes and expands breaking the rock apart.</span>
Answer:
1455.6
Explanation: you first convert 2250ml to l by dividing by 1000 so you get 2.25l then you use Boyles law which is p1v1=p2v2 then insert values
35.75*100=p2*2.25 then divide both sides by 2.25 then you get 1455.6
The electron with its extra packet of energy becomes excited, and promptly moves out of its lower energy level and takes up a position in a higher energy level.
<u>Answer:</u>
The percent composition of this compound is 94%
<u>Explanation:</u>
The reaction can be formed as






Based on no. of iron reacted,

n = m/M

% composition of
= 
= 94%