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777dan777 [17]
2 years ago
11

Find the volume of 3.011x1023 molecules of O2 at STP.

Chemistry
1 answer:
lord [1]2 years ago
8 0

Answer:

6.022 x 1023 molecules = 1 Mole O2 = 22.4L

3.022 x 1023 molecules = 1/2 Mole O2 = 11.2L

The answer is 11.2 Litres

Explanation:

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copper forms two oxides. On heating 1 g of each in hydrogen 0.888 g and 0.798 g of the metal was obtained. Show that the results
Mashutka [201]

Answer:

For the first oxide, 1 g gives 0.888 g of copper.

Dividing by 0.888 tells us that 1.126 g gives 1 g of copper so has 0.126 g of oxygen.

For the second oxide, 1 g gives 0.798 g of copper.

Dividing by 0.798 tells us that 1.253 g gives 1 g of copper so has 0.253 g of oxygen.

So 1 g of copper combines with either 0.126 g or 0.253 g of oxygen.

Within the limits of experimental error, 0.253 is twice 0.126, confirming the law of multiple proportion.

6 0
2 years ago
Read 2 more answers
Please help me, act fast
monitta

Answer:

10g of Pb.

Explanation:

To know which answer is correct, let us calculate the change in the temperature of each substance. This is illustrated below:

For water:

Mass (M) = 10g

Specific heat capacity (C) = 4.18J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 4.18)

ΔT = 2.4°C

Therefore, the change in the temperature of water is 2.4°C

For Ag:

Mass (M) = 10g

Specific heat capacity (C) = 0.235J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 0.235)

ΔT = 42.6°C

Therefore, the change in the temperature of Ag is 42.6°C

For Ca:

Mass (M) = 10g

Specific heat capacity (C) = 0.650J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 0.650)

ΔT = 15.4°C

Therefore, the change in the temperature of Ca is 15.4°C

For Fe:

Mass (M) = 10g

Specific heat capacity (C) = 0.449J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 0.449)

ΔT = 22.3°C

Therefore, the change in the temperature of Fe is 22.3°C

For Pb:

Mass (M) = 10g

Specific heat capacity (C) = 0.160J/g°C

Change in temperature (ΔT) = ..?

Heat (Q) = 100J

Q = MCΔT

Divide both side by MC

ΔT = Q/MC

ΔT = 100 / (10 x 0.160)

ΔT = 62.5°C

Therefore, the change in the temperature of Pb is 62.5°C

Summary:

Substance >> Change in temperature

Water >>>>>> 2.4°C

Ag >>>>>>>>> 42.6°C

Ca >>>>>>>>> 15.4°C

Fe >>>>>>>>> 22.3°C

Pb >>>>>>>>> 62.5°C

From the calculations made above, Pb has the greatest change in temperature

7 0
3 years ago
• This is done through __________ ______________..
cluponka [151]

Answer:

umm...what is the question though?

Explanation:

4 0
3 years ago
For each of the sites specified in the molecules, select whether the site is nucleophilic, electrophilic, or neither. Compound A
GenaCL600 [577]

Answer:

自分の仕事をするthis is your answe but translate it to english

Explanation:

6 0
3 years ago
(free question so use your creativity!!)
raketka [301]

Answer:

Best  

Explanation:

5 0
3 years ago
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