Answer:
i) 796.18 N/mm^2
ii) 1111.11 N/mm^2
Explanation:
Initial diameter ( D ) = 12 mm
Gage Length = 50 mm
maximum load ( P ) = 90 KN
Fractures at = 70 KN
minimum diameter at fracture = 10mm
<u>Calculate the engineering stress at Maximum load and the True fracture stress</u>
<em>i) Engineering stress at maximum load = P/ A </em>
= P / = 90 * 10^3 / ( 3.14 * 12^2 ) / 4
= 90,000 / 113.04 = 796.18 N/mm^2
<em>ii) True Fracture stress = P/A </em>
= 90 * 10^3 / ( 3.24 * 10^2) / 4
= 90000 / 81 = 1111.11 N/mm^2
Answer:
The final temperature is 26.96 F
Explanation:
Initial pressure = 30 lbf/in^2 = 30×1.01325/14.696 = 2.1 bar
Initial temperature = 20 F = (20 - 32)/1.8 + 273 = 266.33 K
From steam table, entropy at 2.1 bar = 7.111 kJ/kg.K
Initial enthalpy = 7.111×266.33 = 1893.9 kJ/kg
Final pressure = 60 lbf/in^2 = 60×1.01325/14.696 = 4.1 bar
From steam table, entropy at 4.1 bar = 6.889 kJ/kg.K
Work = 0.5 Btu = 0.5×1.05506 = 0.5908 kJ
Change in enthalpy (∆H) = work/mass
mass of refrigerant = 0.04 lb = 0.04×0.45359 = 0.0181 kg
∆H = 0.5908/0.0181 = 32.64 kJ/kg
H2 = H1 - ∆H = 1893.9 - 32.64 = 1861.26 kJ/kg
Final temperature = final enthalpy ÷ final entropy = 1861.26 kJ/kg ÷ 6.889 kJ/kg.K = 270.2 K = 1.8(270.2 - 273) + 32 = -5.04 + 32 = 26.96 F
Explanation:
Think of brushes as a sliding contact.
In an alternator the brushes provide power to the field coil which is physically mounted on the rotating shaft. They provide this direct current through two slip rings.
By controlling the power flow to the field, the power output of the alternator can be controlled. A regulator circuit is used to control the field so that the output voltage is maintained to about 13.5 to 14.5 VDC.
FUN FACT: Many brush holders have a small holes near the brush exit. When you assemble the alternator you physically push the brushes all the way into their holder and then thread a small wire through these hole. After the alternator is assembled you can pull the wire out and the brushes will snap into position.
Answer:
True, That is correct. Soil removed from an excavation site is indeed called spoil.
Spoil definition: The waste material (such as soil) brought up during the course of an excavation.
Hope I helped! Sorry if not. Have a wonderful week and follow me for more help! Remember your worth and love yourself! Adíos! ;D
Answer:
The high conversion in a CSTR with not very well mixing occurs mostly if the reactor is micro reactor.
From Literature, mixing due to diffusion depends on concentration or temperature gradients. This is commonly represented in micro reactors.
Also, the residence time distribution (RTD) Analysis provides information on how long the various components of fluid have been in the reactor which leads to more conversion in some cases of fluid reaction.