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2 years ago

What is slope of a graph in physics

Physics

1 answer:

Virty [35]2 years ago

5 0

Answer:

slope $=\frac{y_{2} -y_{1} }{x_2-x_1}$

Explanation:

the slope of a graph in general is the following

slope $=\frac{y_{2} -y_{1} }{x_2-x_1}$ (1)

1) Pick two points on the graph

2) The coordinate of the first point is $(x_1,y_1)$ , while the second point is $(x_2,y_2)$ .

3) Substitute with the coordinate values in equation (1) to get the slope

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an object is thrown horizontally off a cliff with an initial velocity of 5.0 meters per second. the object strikes the ground 3.

Olegator [25]

You know that the formula for finding horizontal displacement is;

s=uₓt
s=(5 m/s)(3s)
s=15 m

Therefore, the ball travelled 15 m.

Hope I helped :)

7 0

3 years ago

Read 2 more answers

Write the equation in slope-intercept form <br> x-2y=4

maxonik [38]

Answer:

$y=\frac{1}{2}x-2$

Explanation:

Slope-intercept form means we want the y to be by itself in the equation. Every thing we do will be about getting the y alone on the left side of the equation

To start we should move x to the left hand side. We can do this by subtracting x from both sides. That way, there is an x on the right, but not the left.

x-x-2y=4-x

this gives us

-2y=4-x

Great! So now what? Well, the y isn't by itself yet because it still is being multiplied by negative two (-2). In order to move it from the left side to the right side, we have to do the opposite of multiply; divide. So, we will divide both sides by -2

$\frac{-2y}{-2} =\frac{4}{-2} -\frac{x}{-2}$

-2 divided by -2 is 1, 4 divided by -2 is -2, and -x divided by -2 is $\frac{1}{2}x$

This gives us the answer: $y=\frac{1}{2}x-2$

Tips:

A negative divided by a negative is a positive ex: -4 divided by -2 is positive 2

If you are subtracting by a negative number, you are actually adding by a positive ex: 2-(-2) is actually 2+2

Don't be afraid to have fractions in your equations

Whatever you do to the one side of the equation, you must do it to the other side as well. Multiply the left side by 2? You HAVE TO multiply the right side by two as well. Add 3 to the right side? You HAVE TO add 3 to the left.

For problems like this (and when you have access to the internet), where you need to rewrite an equation, double check your work on desmos, which is an online graphing calculator. Input both the original equation and the equation you rewrote, and if they don't create the same line, you did something wrong.

8 0

3 years ago

Rod AB has a diameter of 200mm and rod BC has a diameter of 150mm. Find the required temperature increase to close the gap at C.

Leni [432]

Answer:

$T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}$

Explanation:

The given data :-

Diameter of rod AB ( d₁ ) = 200 mm.

Diameter of rod BC ( d₂ ) = 150 mm.

The linear co-efficient of thermal expansion of copper ( ∝ ) = 1.6 × 10⁻⁶ /°C

The young's modulus of elasticity of copper ( E ) = 120 GPa = 120 × 10³ MPa.
Consider the required temperature increase to close the gap at C = T °C
Consider the change in length of the rod = бL

Solution :-

$\begin{aligned}\sum H& =0\\-R_A+R_C&=0\\R_A&=R_C\\R_A&=R\\R_C&=R\\R_{A}&=\text{reaction\:force\:at\:A}\\R_{C}&=\text{reaction\:force\:at\:C}\\\sigma_{AB}&=\text{axial\:stress\:at\:A}\\\sigma_{BC}&=\text{axial\:stress\:at\:B}\\\sigma_{AB}&=\frac{R}{A_{A}}\\&=\frac{R_{A}}{A_{A}}\\\sigma_{BC}&=\frac{R_{B}}{A_{B}}\\&=\frac{R}{A_{B}}\\\frac{\sigma_{AB}}{\sigma_{BC}}&=\frac{A_{B}}{A_{B}}\\&=\frac{\frac{\pi}{4}\cdot 150^{2}}{\frac{\pi}{4}\cdot 200^{2}}\\&=\frac{9}{16}\end{aligned}$

$\begin{aligned}\delta L&= (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\0& = (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\&=\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{AB}+\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{BC}\\&=2\:\alpha\:T\:L-\frac{L}{E}(\sigma_{AB}+\sigma_{BC})\\T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}\end{aligned}$

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4 years ago

A ball rolls horizontally off an incline, at velocity of 8.00m/s l. If the incline is 3.50m above the ground below determine:

Nesterboy [21]

Answer:

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3 years ago

a bat experts a 120 N force on a 0.134 kg baseball for 0.04 seconds. what impolse is excerted on the bat

musickatia [10]

The impulse exerted by a force F on an object in a time $\Delta t$ is given by
$I = F \Delta t$
In our problem, we have a force of 120 N: F=120 N, applied to the baseball for a time of $\Delta t=0.04 s$ . Therefore the impulse is
$I=F \Delta t = (120 N)(0.04 s)=4.8 Ns$

3 0

4 years ago

What is slope of a graph in physics​

What is slope of a graph in physics