Answer:
Range, 
Explanation:
The question deals with the projectile motion of a particle mass M with charge Q, having an initial speed V in a direction opposite to that of a uniform electric field.
Since we are dealing with projectile motion in an electric field, the unknown variable here, would be the range, R of the projectile. We note that the electric field opposes the motion of the particle thereby reducing its kinetic energy. The particle stops when it loses all its kinetic energy due to the work done on it in opposing its motion by the electric field. From work-kinetic energy principles, work done on charge by electric field = loss in kinetic energy of mass.
So, [tex]QER = MV²/2{/tex} where R is the distance (range) the mass moves before it stops
Therefore {tex}R = MV²/2QE{/tex}
Answer: 2812500 joules
Explanation:
Mass of car = 1500kg
Velocity of car = 75mph
Kinetic energy = ?
Recall that kinetic energy is the energy possessed by a moving object, and it depends on its mass M and velocity, V
Thus, Kinetic energy = 1/2 x mv^2
= 1/2 x 1000kg x (75mph)^2
= 0.5 x 1000kg x (75mph)^2
= 500 x 5625
= 2812500 joules
Thus, the car travels with a kinetic energy of 2812500 joules
If you do this on Earth, then the acceleration of the falling object is 9.8 m/s^2 ... NO MATTER what it's mass is.
If its mass is 10 kg, then the force pulling it down is 98.1 Newtons. Most people call that the object's "weight".