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cupoosta [38]
3 years ago
7

Static electricity occurs when two objects have different electrical charges. When objects are rubbed together, the electrons fr

om one object can hop to the other, causing them to take on a positive or negative charge. Positively charged objects repel each other, so when your hair stands on end, that is due to a positive electrical charge transferred from another object, usually a hat or hair brush. What would be one way to avoid static electricity
Physics
2 answers:
denis23 [38]3 years ago
5 0

Answer:Alter your winter wardrobe. Wearing your favorite wool sweater or socks might seem perfect for keeping warm, but your chances of being shocked will rise while wearing wool and certain synthetic fabrics, including nylon and polyester. ...

Humidify your home. ...

Use dryer sheets. ...

Keep touching metal.

Explanation:hope that helps

damaskus [11]3 years ago
5 0

Answer:

Run a metal clothes hanger across your dry hair.

Explanation:

Absorb electrical currents in your hair by rubbing a metal hanger over your hair. Hold the hanger so it is touching your head and move it slowly downward.

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The air temperature in a 28 in.3 container with a free sliding piston is initially measured at 45 °
sergiy2304 [10]

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

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A rod of length L and mass M has a nonuniform mass distribution. The linear mass density (mass per length) is λ=cx2, where x is
grigory [225]

Answer:

Explanation:

λ=c x²

c = λ / x²

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so its dimensional formula is ML⁻¹

x is length so its dimensional formula is L

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= ML⁻³

B )

We shall find out the mass of the rod with the help of given expression of mass per unit length and equate it with given mass that is M

The mass in the rod is symmetrically distributed on both side of middle point.

we consider a small strip of rod of length dx at x distance away from middle point

its mass dm = λdx = cx² dx

By integrating it from -L to +L we can calculate mass of whole rod , that is

M = ∫cx² dx

= [c x³ / 3] from -L/2 to +L/2

= c/3 [ L³/8 + L³/8]

M = c L³/12

c = 12 M L⁻³

C ) Moment of inertia of rod

∫dmx²

= ∫λdxx²

= ∫cx²dxx²

= ∫cx⁴dx

= c x⁵ / 5 from - L/2 to L/2

= c / 5 ( L⁵/ 32 +L⁵/ 32)

= (2c / 160)L⁵

= (c / 80) L⁵

= (12 M L⁻³/80)L⁵

= 3/20 ML²

=

=

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