Answer:
The initial height of an object above ground before being launched straight up in the air
Step-by-step explanation:
we have
we know that
The number 72 represent the y-intercept of the function
The y-intercept is the value of y when the value of x is equal to zero
In this problem
The value of h when the value of t is zero
Therefore
The initial height of an object above ground before being launched straight up in the air
Equation :
This parabola is facing downwards and highest point of the parabola is it's vertex.
Highest point is (-2,2)
so the vertex is (-2,2)
The graph is passing through (-1,0)
Equation in vertex form is
Substitute back in Equation
the graph has two x intercepts -1 and -3
that means (x+1) and (x+3) are the factors
multiply factors to get the equation in standard form
-2x^2-8x-6=0
Sin(35) = Opp./Hypo
sin(35) = 18/x
so
x = 18/sin(35)
x = 18 / 0.57357644
x = 31.38
x = 31.4
Answer is C. 31.4
Answer:
what is the problem
Step-by-step explanation:
i need picture
