How many grams of nitrogen are contained in a sample of C4H9N302 that also
1 answer:
Empirical formula = mol ratio
mol H = 9.42 x 10²⁴ : 6.02 x 10²³ = 15.648
mol N = 3/9 x 15.648 = 5.216
mass N = 5.216 x 14 g/mol =73.024 g
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