Answer:
1. 0.035 mole
2. 2.1 g
3. 2 mL
Explanation:
From the question given above, the following data were obtained:
Molarity of acetic acid = 0.035 mol/L.
1. Determination of the number of mole of acetic acid needed.
Molarity of acetic acid = 0.035 mol/L.
Volume of solution = 1 L
Mole of acetic acid =?
Molarity = mole /Volume
0.035 = mole / 1
Mole of acetic acid = 0.035 mole
2. Determination of the mass of acetic acid, CH₃COOH.
Mole of CH₃COOH = 0.035 mole
Molar mass of CH₃COOH = 12 + (3×1) + 12 + 16 + 16 + 1
= 12 + 3 + 12 + 16 + 16 + 1
= 60 g/mol
Mass of CH₃COOH =?
Mole = mass / Molar mass
0.035 = Mass of CH₃COOH / 60
Cross multiply
Mass of CH₃COOH = 0.035 × 60
Mass of CH₃COOH = 2.1 g
3. Determination of the volume.
Mass = 2.1 g
Density = 1.05 g/mL
Volume =?
Density = mass / volume
1.05 = 2.1 / volume
Cross multiply
1.05 × volume = 2.1
Divide both side by 1.05
Volume = 2.1 / 1.05
Volume = 2 mL
D.4s this would be the answer because after eight electrons are added to the third orbital two have to be added to the fourth before more can be added to the third one. The third orbital can hold 18 electrons, but it first has to have eight, then two on the fourth orbital, then the rest of the ten can be added
Lewis structure of N2O5 is :
:O : : O:
II II
N N
/ \ / \
:O: :O: :O :
.. ..
or or O2 N-O- NO2
<span>So the covalency of nitrogen is 3 only as one pair of electrons is coordinated with oxygen shown here as having all the six electrons intact.
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