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andrey2020 [161]
2 years ago
13

a 1kg ball is bening pushed by the rod to move in horizontal groved smooth slot if it startes from angle teta = zero degree . de

termaine the force the rod exertes on the ball at teta is =15 dgree if ai this instant the rod moves at angular speed of teta = 1 rad per sec end with angular acceleration theta = 2 rad persec and square the ball is only in contact with the outer side of the slot​
Physics
1 answer:
viva [34]2 years ago
6 0

The force the rod exerts on the ball at the given angle is determined as 3.94 N.

<h3>Force exerted on the rod by the ball</h3>

The force exerted is calculated as follows;

F = ma

F = mv²/r

F = mω²r

where;

  • m is mass of the ball
  • ω is angular speed of the ball
  • r is radius of the path

r = 2cosθ

<h3>Angular speed when the ball moves 15 degrees</h3>

ωf² = ωi² + 2αθ

where;

  • θ is angular displacement in radians, 15⁰ = 15 x π/180 rad

ωf² = (1)² + 2(2)(15 x π/180)

ωf² = 2.04

ωf = √2.04

ωf = 1.428 rad/s

F = mω²(2cosθ)

F = (1)(1.428)²(2 x cos15)

F = 3.94 N

Learn more about force here: brainly.com/question/12970081

#SPJ1

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Answer:

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3 years ago
2) 1. A vibration of an electric charge.
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<h2> Answers</h2>

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On a cold winters day if you left a cup of water sitting outside it could freeze heat is transferred out of the water describe t
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The water molecules would slow down, and as they slow down, the heat created from their movement would cease.
4 0
4 years ago
An RL circuit contains a resistor with R = 6800 Ω and an inductor with L = 2300 µH. If the impedance of this circuit is 160,000
Rainbow [258]

| Impedance | = √ [R² +(ωL)²]

R² = 6800² = 4.624 x 10⁷
 
(ωL)² = (2 · π · f · 2.3 · 10⁻³)²

          = 2.0884 x 10⁻⁴  f²

| Z | =  √[ (4.624 x 10⁷) + (2.0884 x 10⁻⁴ f²) ]  =  1.6 x 10⁵

     (1.6 x 10⁵)²  =  (4.624 x 10⁷) + (2.0884 x 10⁻⁴ f²)

     (2.56 x 10¹⁰) - (4.624 x 10⁷)  =  2.0884 x 10⁻⁴ f²


Frequency² =   (2.56 x 10¹⁰ - 4.624 x 10⁷)  /  2.0884 x 10⁻⁴

                    =       2.555 x 10¹⁰ / 2.0884 x 10⁻⁴

                    =          1.224 x 10¹⁴ 

                    =          122,400 GHz          <== my calculation

                                      11.1 MHz           <== online impedance calculator

Obviously, I must have picked up some rounding errors
in the course of my calculation. 
  











7 0
3 years ago
The persistence of vision for normal eye is
attashe74 [19]

Answer:

The answer is 1/16

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6 0
4 years ago
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