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3 years ago

Which resultant force is NOT possible if 50 N force and a 60 N force act concurrently?

Physics

1 answer:

Sergio [31]3 years ago

3 0

Answer:

The options are not shown, so i will answer in a general way.

Suppose the case where the forces act in opposite directions, then we need to subtract the forces, and we know that the magnitude of the resultant force will be:

60N - 50N = 10N

Now, suppose the case where both forces act in the exact same direction, in that case, we will add the forces to get:

60N + 50N = 110N

Then the only range of forces that we can get in this system, are the forces such:

10N ≤ F ≤ 110N

Any resultant force outside that range is not possible in this situation.

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3 years ago

Read 2 more answers

Two wires carrying equal currents exert a force ???????? on each other. (a) The current in each wire is doubled, while the dista

sweet-ann [11.9K]

a) The magnetic field created by a current-carrying wire is proportional to the current:

B ∝ I, B = magnetic field strength, I = current

The magnetic force acting on a current-carrying wire immersed in a magnetic field is proportional to the current and the magnetic field strength:

F ∝ IB, F = magnetic force, I = current, B = magnetic field strength

Let's focus on wire 1.

Since wire 2's current is doubled, wire 2 produces a magnetic field twice as strong as before.

Wire 1's current is also doubled, therefore we now have a wire having twice as strong a current immersed in twice as strong a magnetic field. The magnetic force on wire 1 (and you can make a similar argument for wire 2) will be four times as strong as before.

b) The general formula for the magnetic force acting on a current-carrying wire immersed in a magnetic field is given by:

F = IL×B

F = magnetic force vector

I = current

L = vector having a magnitude equal to wire length and representing direction of current

B = magnetic field vector

Note we are taking a cross product of the IL and B vectors, not the product of two scalar quantities.

The very nature of the cross product means that if L and B are parallel to each other, F = 0N

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3 years ago

A charged particle moving along the +x-axis enters a uniform magnetic field pointing along the +z-axis. A uniform electric field

Brums [2.3K]

Answer:

the electric field direction should be in positive y axis

Explanation:

Lets assume that charge on particle is positive and it isequal to +q

First calculate the magnetic force on it

$F_B = q V\times B =qVBsin\theta$

for direction

use Right Hand Rule which will give the direction and by using his the direction will come towards negative y axis.

As given in the question that charge particle does not change their velocity so we need to apply electric field in such a way that electric force direction should be opposite to the magnectic field.

and magnitude should be same as magnectic force and also direcion of electric force depend on the direction of elecric field when charge is positive because electric force $F_E = qE$

Hence the electric field direction should be in positive y axis

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4 years ago

suppose that the man pictured on the front side is orbiting the earth (mass=5.98 x 10^24kg at a distance of 310 miles above the

wlad13 [49]

Answer:

a = 9.81[m/s^2]; v = 18683.5[m/s]

Explanation:

The stament of the problem is:

Suppose that the man pictured on the front side is orbiting the earth (mass = 5.98 x 1024kg) at a distance of 310 miles (1600 meters = 1 mile) above the surface of the earth (radius = 4000 miles).

a. What acceleration does he experience due to the earth's pull?

b. What tangential velocity must he possess in order that he orbit safely (in m/s)?

First we need to convert all the initial data to units of the SI

Rs = 310 [mil] = 498897 [m]

RT= 400 [mil] = 643738 [m]

r = Rs + RT = 1142635 [m] "distance from the center of the earth to the man"

$F=G*\frac{M*m}{r^{2} } \\where:\\$

G = universal gravitational constant

M = mass of the earth [kg]

m = mass of the man [kg]

r = distance from the center of the earth to the man [m]

The acceleration he is experimenting is the same acceleration given by the gravity, therefore:

a = g = 9.81[m/s^2]

To find the tangential velocity, we must determinate the force exerted by the earth.

Now we will find the force exerted by the gravity when the man is orbiting the earth at distance r.

$G = 6.67*10^{-11} [\frac{N*m^{2} }{kg^{2} } ]\\M=5.98*10^{24}[kg]\\ m=100 [kg]\\Replacing:\\F = G*\frac{M*m}{r^{2} }$

$F = 6.67*10^{-11}*\frac{5.98*10^{24}*100 }{1142635^{2} } \\ F= 30550 [N]$

And this force will be equal to the following expression:

$F = m*\frac{v^{2} }{r} \\where:\\v= tangential velocity [m/s]\\v=\sqrt{\frac{F*r}{m} } \\v=\sqrt{\frac{30550*1142635}{100} } \\v=18683.5[m/s]$

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3 years ago