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Ugo [173]
3 years ago
15

A submarine is stranded on the bottom of the ocean with its hatch 25 m below the surface. In this problem, assume the density of

sea water is 1.03 × 103 kg/m3. show answer No Attempt Calculate the force, in newtons, needed to open the hatch from the inside, given it is circular and 0.25 m in diameter. The air pressure inside the submarine is 1.00 atm.
Physics
1 answer:
topjm [15]3 years ago
4 0

Answer:

F = 49.55 x 10 ³ N

Explanation:

Given :

ρ = 1.03 x 10³ kg / m³ ,  h= 25 m , g = 9.8 m / s² , r = 0.25 m

So solve to determine force

A = π * r² = π * (0.25 m)²

A = 196.34 x 10 ⁻³ m²

The pressure of the water

P = F / A

Determine the force using the pressure into the area

F = P * A

P = ρ * g * h

Replacing numeric

P = 1.03 x 10³ kg / m³ * 9.8 m / s² * 25 m

P = 252.35 x 10³ N / m²

F = P * A  ⇒ F = 252.35 x 10³ N / m²  * 196.34 x 10 ⁻³ m²  

F = 49.55 x 10 ³ N

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Answer:

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Explanation:

Given the following data;

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To find the final volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

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Substituting into the equation, we have;

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