Ask question

Ask question

All categories

3 years ago

15

A submarine is stranded on the bottom of the ocean with its hatch 25 m below the surface. In this problem, assume the density of

sea water is 1.03 × 103 kg/m3. show answer No Attempt Calculate the force, in newtons, needed to open the hatch from the inside, given it is circular and 0.25 m in diameter. The air pressure inside the submarine is 1.00 atm.

1 answer:

topjm [15]3 years ago

4 0

Answer:

F = 49.55 x 10 ³ N

Explanation:

Given :

ρ = 1.03 x 10³ kg / m³ , h= 25 m , g = 9.8 m / s² , r = 0.25 m

So solve to determine force

A = π * r² = π * (0.25 m)²

A = 196.34 x 10 ⁻³ m²

The pressure of the water

P = F / A

Determine the force using the pressure into the area

F = P * A

P = ρ * g * h

Replacing numeric

P = 1.03 x 10³ kg / m³ * 9.8 m / s² * 25 m

P = 252.35 x 10³ N / m²

F = P * A ⇒ F = 252.35 x 10³ N / m² * 196.34 x 10 ⁻³ m²

F = 49.55 x 10 ³ N

You might be interested in

This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The mag

Dmitry [639]

Answer:

Part a)

$F = 135.7 N$

Part b)

$F = 62.5 N$

Explanation:

Part a)

If block is sliding up then net force must be zero and friction will be in opposite to the direction of motion of the block

$Fcos\theta = mg + F_f$

$Fsin\theta = F_n$

so we have

$Fcos\theta = mg + \mu(Fsin\theta)$

$F(cos\theta - \mu sin\theta) = mg$

$F = \frac{mg}{cos\theta - \mu sin\theta}$

$F = \frac{55}{cos50 - 0.310(sin50)}$

$F = 135.7 N$

Part b)

If block is sliding down then net force must be zero and friction will be in opposite to the direction of motion of the block

$Fcos\theta = mg - F_f$

$Fsin\theta = F_n$

so we have

$Fcos\theta = mg - \mu(Fsin\theta)$

$F(cos\theta + \mu sin\theta) = mg$

$F = \frac{mg}{cos\theta + \mu sin\theta}$

$F = \frac{55}{cos50 + 0.310(sin50)}$

$F = 62.5 N$

6 0

3 years ago

A speeding motorist traveling with velocity Vm is spotted by a police car. The police car is initially at rest, but the instant

Svetlanka [38]

Answer:

Explanation:

Given

Let us suppose police car and motorist travel in straight line and police car catches motorist after s distance

Distance travel by motorist

$s=v_mt$ ----1

Distance traveled by Police car

$s=ut+\frac{at^2}{2}$

$s=0+\frac{a_pt^2}{2}$

$s=\frac{a_pt^2}{2}$ ----2

from 1 & 2 we get

$t=\frac{2v_m}{a_p}$

(a)Velocity of Police car after t sec

$v=u+a_pt$

$v=0+a_p\times \frac{2v_m}{a_p}$

$v=2v_m$

(b)time taken by police car is

$t=\frac{2v_m}{a_p}$

(c)Distance travel by police car $=\frac{2v_m^2}{a_p}$

7 0

3 years ago

Your backpack has a mass of 8 kg. You drop it from a height of 1.3m. How much work is done by gravity as the backpack falls?

olga_2 [115]

Answer:

The answer is C.

Explanation:

I guessed and it was right

6 0

3 years ago

Read 2 more answers

PSYCHOLOGY <br> Which of these statements are false ?

nataly862011 [7]

Answer:

The false statement has to be that neruotransmitters are in the spinal cord.

Explanation:

Neruotransmitters are in no was associated with the spinal cord. That is more related to nerves and muscles. Neurotransmitters are in the Phasma Membrane acording to sciencedirect.com.

4 0

2 years ago

If Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?

Nastasia [14]

Answer:

10g

Explanation:

As the Law of Conservation of Mass states that " Mass can neither be created nor be destroyed in a chemical reaction".

Though melting of tin isn't a chemical change, the same logic is applied here...

Hence,

The mass of tin will be 10 g itself...

7 0

3 years ago

Read 2 more answers