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Over [174]
3 years ago
11

How do i solve for x (ax+bx)/3=c in terms of a and b and c

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0
Already in terms of c x(ax+bx)/3=c
(ax^2 + bx^2)/3=c. Multiply parentheses by x
ax^2 + bx^2=3c. Multiply each side by 3
ax+bx=√3c. Take the square root of both sides
x(a+b)=√3c
a+b=√3c/x
a=√3c/x - b or b=√3c/x - a
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huma has 4 bags of square inch tiles with 6 in each bag she uses them to meaure the area of a rectangle on her homework. ahter c
poizon [28]

Answer:

20 square inches

Step-by-step explanation:

No. of bags Huma has : 4

No. of tiles in one bag: 6

Total no . of tiles in 4 bag = 4 * No. of tiles in one bag

                                             = 4*6 = 24

No of tiles left with huma = 4

Let x be the no of tiles used to cover rectangle

Hence,

sum of no. of tiles left with huma and no of tiles used to cover rectangle should be equal to Total no . of tiles in 4 bag

mathematically

no. of tiles left with huma(4) + no of tiles used to cover rectangle (x) =  Total no . of tiles in 4 bag (24)

4 + x = 24

subtracting 4 from both sides

4 + x -4 = 24 - 4

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