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Mila [183]
3 years ago
9

What is the first step of the engineering design process?

Engineering
2 answers:
scoundrel [369]3 years ago
5 0

Answer:

The first step  is to identify the need and constraints

Explanation:

raketka [301]3 years ago
3 0

Answer:

The first step  is to identify the need and constraints

Explanation:

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Me ayudas plis noce ​
alekssr [168]

Answer:

Explanation:

7 0
2 years ago
A two-phase mixture of water and steam with a quality of 0.63 and T = 300F expands isothermally until only saturated vapor rema
VMariaS [17]

Answer:

Explanation:

Hello!

To solve this problem you must follow the following steps, which are fully registered in the attached image.

1. Draw the complete outline of the problem.

2. Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)

through prior knowledge of two other properties.

3. Use temodynamic tables to find the density of water in state 1, by means of temperature and quality, with this value and volume we can find the mass.

3. Use thermodynamic tables to find the internal energy in state 1 and two using temperature and quality.

4. uses the first law of thermodynamics that states that the energy in a system is always conserved, replaces the previously found values ​​and finds the work done.

5. draw the pV diagram using the 300F isothermal line

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3 years ago
If my friend have the corona what do I do
nordsb [41]
(E. Call the hospital to take them away
5 0
3 years ago
Read 2 more answers
A silicon diode has a saturation current of 6 nA at 25 degrees Celcius. What is the saturation current at 100 degrees Celsius?
Illusion [34]

Answer:

0.0659 A

Explanation:

Given that :

I_{0}  =  6nA ( saturation current )

at 25°c = 300 k ( room temperature )

n = 2  for silicon diode

Determine the saturation current at 100 degrees = 373 k

Diode equation at room temperature = I = Io \frac{V}{e^{0.025*n} }

next we have to determine the value of V at 373 k

q / kT = (1.6 * 10^-19) / (1.38 * 10^-23 * 373) = 31.08 V^-1

Given that I is constant

Io = \frac{e^{0.025*2} }{31.08} =  0.0659 A

3 0
3 years ago
A 150 MVA, 24 kV, 123% three-phase synchronous generator supplies a large network. The network voltage is 27 kV. The phase angle
Aleks04 [339]

Answer:

the generator induced voltage is 60.59 kV

Explanation:

Given:

S = 150 MVA

Vline = 24 kV = 24000 V

X_{s} =1.23(\frac{V_{line}^{2}  }{s} )=1.23\frac{24000^{2} }{1500} =4723.2 ohms

the network voltage phase is

V_{phase} =\frac{V_{nline} }{\sqrt{3} } =\frac{27}{\sqrt{3} } =15.58kV

the power transmitted is equal to:

|E|=\frac{P*X_{s} }{3*|V_{phase}|sinO } ;if-O=60\\|E|=\frac{300*4.723}{3*15.58*sin60} =34.98kV

the line induced voltage is

|E_{line} |=\sqrt{3} *|E|=\sqrt{3} *34.98=60.59kV

7 0
3 years ago
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