Answer:
I used iteration to improve my skills in sports.
Answer:
The kinetic energy is 6.4 kJ and the distance traveled by the system is 256 m.
Explanation:
Given the mass of the system
is 8 kg.
And initially, it moves with a velocity
40 m/s.
Also, it experiences 25 N force
which opposes its motion.
We need to find the kinetic energy and the distance traveled by the system
before going to rest.
It will be the kinetic energy of 8 kg mass with 40 m/s velocity that is transferred to work.
![K.E=\frac{1}{2}mv^2\\K.E=\frac{1}{2}\times 8\times 40^2\\K.E= 6400\ J\\K.E=6.4\ kJ](https://tex.z-dn.net/?f=K.E%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%5C%5CK.E%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%208%5Ctimes%2040%5E2%5C%5CK.E%3D%206400%5C%20J%5C%5CK.E%3D6.4%5C%20kJ)
Since this system is opposed by 25 N force, work done by the force will be.
And the kinetic energy transferred to work. We can equate them.
![f(d)=6400\\25(d)=6400\\d=\frac{6400}{25}=256\ m](https://tex.z-dn.net/?f=f%28d%29%3D6400%5C%5C25%28d%29%3D6400%5C%5Cd%3D%5Cfrac%7B6400%7D%7B25%7D%3D256%5C%20m)
So, the system will travel 256 m.
Answer:
![T_A_C = 6.296 kN](https://tex.z-dn.net/?f=%20T_A_C%20%3D%206.296%20kN%20)
Explanation:
Given:
Required:
Find the tension TAC and magnitude R of this downward force.
First calculate ![\alpha, \beta, \gamma](https://tex.z-dn.net/?f=%20%5Calpha%2C%20%5Cbeta%2C%20%5Cgamma%20)
![\alpha = tan^-^1 =\frac{40}{50} = 38. 36](https://tex.z-dn.net/?f=%20%5Calpha%20%3D%20tan%5E-%5E1%20%3D%5Cfrac%7B40%7D%7B50%7D%20%3D%2038.%2036%20)
<em>To Find tension in AC and magnitude R, use sine rule</em>.
![\frac{sin a}{T_A_C} = \frac{sin b}{T_A_B} = \frac{sin c}{R}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bsin%20a%7D%7BT_A_C%7D%20%3D%20%20%5Cfrac%7Bsin%20b%7D%7BT_A_B%7D%20%20%3D%20%20%5Cfrac%7Bsin%20c%7D%7BR%7D%20%20)
Substitute values:
![\frac{sin 38.36}{T_A_C} = \frac{sin 59.04}{8.7} = \frac{82.6}{R}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%2038.36%7D%7BT_A_C%7D%20%3D%20%20%5Cfrac%7Bsin%2059.04%7D%7B8.7%7D%20%20%3D%20%20%5Cfrac%7B82.6%7D%7BR%7D)
Solve for T_A_C:
![T_A_C = 8.7 * \frac{sin 38.36}{sin 59.04} =](https://tex.z-dn.net/?f=%20T_A_C%20%3D%208.7%20%2A%20%5Cfrac%7Bsin%2038.36%7D%7Bsin%2059.04%7D%20%3D%20)
![T_A_C = 8.7 * 0.724 = 6.296 kN](https://tex.z-dn.net/?f=%20T_A_C%20%3D%208.7%20%2A%200.724%20%3D%206.296%20kN%20)
Solve for R.
![R = 8.7 * \frac{sin 82.6}{sin 59.04} =](https://tex.z-dn.net/?f=%20R%20%3D%208.7%20%2A%20%5Cfrac%7Bsin%2082.6%7D%7Bsin%2059.04%7D%20%3D%20)
![R = 8.7 * 1.156](https://tex.z-dn.net/?f=%20R%20%3D%208.7%20%2A%201.156%20)
R = 10.06 kN
Tension AC = 6.296kN
Magnitude,R = 10.06 kN
Answer: Try Restarting Or a shut down
Explanation:
Answer:
The FSM uses the states along with the generation at the P output on each of the positive edges of the CLK. The memory stores the previous state in the machine and the decoder generates a P output based on the previous state.
Explanation:
The code is in the image.