Las hojas de cálculo en Excel facilitan los cálculos numéricos a través del uso de fórmulas; de manera fácil y rápida se pueden hacer operaciones aritméticas sobre cientos de miles de datos numéricos; por lo que se puede actualizar o corregir cualquiera de los datos numéricos y las operaciones se recalculan
I would go with C but i am not 100 percent on that
Answer:
Cyclical
Explanation:
I looked at the next question on edgenuity and it said it in the question.
Answer:
# Initialize a dictionary with the keys
contestants = {"Darci Lynne":0, "Angelica Hale":0, "Angelina Green":0};
# Repeatedly prompt the user for a contestant name to vote for
while True:
# Prompting user for contestant name
cName = input("Enter contestant name to vote: ");
# Checking for Done
if cName.lower() == "done":
break;
# Checking in dictionary
if cName in contestants.keys():
# Updating vote value
contestants[cName] += 1
# New entry
else:
contestants[cName] = 1
# Printing header
print("\n%-20s %-15s\n" %("Contestant Name", "Votes Casted"))
# Printing results
for contestant in contestants:
print("%-23s %-15d" %(contestant, contestants[contestant]))
Answer:
HIGH from the supply voltage
LOW from ground
Explanation:
The answer depends on the kind of system and the purpose of the signal. But for practical reasons, in a DIGITAL system where 5V is HIGH and 0 V is LOW, 5 volts can be taken from the supply voltage (usually the same as high, BUT must be verified), and the LOW signal from ground.
If the user has a multimeter, it must be set to continuous voltage on 0 to 20 V range. Then place the probe in the ground of the circuit (must be a big copper area). Finally leave one probe in the circuit ground and place the other probe in some test points to identify 5 v.
