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Tresset [83]
2 years ago
12

Identify the right components for gsm architecture that consists of the hardware or physical equipment such as digital signal pr

ocessors, radio transceiver, display, battery, case and sim card
Engineering
1 answer:
sergiy2304 [10]2 years ago
6 0

The right components for gsm architecture that consists of the hardware or physical equipment such as digital signal processors, radio transceiver, display, battery, case and sim card is the Mobile station.

<h3>What are the 4 main components?</h3>

In GSM, a cell station includes 4 fundamental additives: Mobile termination (MT) - gives not unusualplace features consisting of: radio transmission and handover, speech encoding and decoding, blunders detection and correction, signaling and get right of entry to to the SIM. The IMEI code is connected to the MT.

Under the GSM framework, a cell tele cell smartphone is called a Mobile Station and is partitioned into  wonderful additives: the Subscriber Identity Module (SIM) and the Mobile Equipment (ME).

Read more about the mobile station:

brainly.com/question/917245

#SPJ4

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How do you solve this. I dont know how so I need steps if you dont mind
galben [10]

Explanation:

all I know is every number that have a bar on is equal to one

4 0
2 years ago
In the engineering design and prototyping process, what is the advantage of drawings and symbols over written descriptions?
MrMuchimi

The advantages that can be associated to

drawings and symbols over written descriptions in engineering design and prototyping process are;

Communicate design ideas as well as technical information to engineers.

Symbols and drawings can be universal which means it is easy to interpret any where by professionals.

  • An engineering drawing serves as complex dimensional object and symbol use by engineer to communicate.

  • Drawings and symbols makes it easier to communicate design ideas and technical information to engineers and and how the process will go.

Therefore, drawings and symbols is universal to all engineer unlike written one.

Learn more at:

brainly.com/question/20925313?referrer=searchResults

4 0
3 years ago
2. Write a Java program that generates a new string by concatenating the reversed substrings of even indexes and odd indexes sep
Nana76 [90]

Answer:

  1. public class Main {
  2.    public static void main(String[] args) {
  3.        String testString = "abscacd";
  4.        String evenStr = "";
  5.        String oddStr = "";
  6.        for(int i=testString.length() - 1; i >= 0; i--){
  7.            if(i % 2 == 0){
  8.                evenStr += testString.charAt(i);
  9.            }
  10.            else{
  11.                oddStr += testString.charAt(i);
  12.            }
  13.        }
  14.        System.out.println(evenStr + oddStr);
  15.    }
  16. }

Explanation:

Firstly, let declare a variable testString to hold an input string "abscacd" (Line 1).

Next create another two String variable, evenStr and oddStr and initialize them with empty string (Line 5-6). These two variables will be used to hold the string at even index and odd index, respectively.

Next, we create a for loop that traverse the characters of the input string from the back by setting initial position index i to  testString.length() - 1  (Line 8). Within the for-loop, create if and else block to check if the current index, i is divisible by 2, (i % 2 == 0), use the current i to get the character of the testString and join it with evenStr. Otherwise, join it with oddStr (Line 10 -14).

At last, we print the concatenated evenStr and oddStr (Line 18).  

4 0
3 years ago
Which statement about lean manufacturing is true when you compare it to mass production?
Len [333]
Where are the statements then bbs lol
6 0
3 years ago
For each function , sketch the Bode asymptotic magnitude and asymptotic phase plots.
horrorfan [7]

Answer:

attached below

Explanation:

a) G(s) = 1 / s( s+2)(s + 4 )

Bode asymptotic magnitude and asymptotic phase plots

attached below

b) G(s) = (s+5)/(s+2)(s+4)

phase angles = tan^-1 w/s , -tan^-1 w/s , tan^-1 w/4

attached below

c) G(s)= (s+3)(s+5)/s(s+2)(s+4)

solution attached below

5 0
3 years ago
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