Answer:
42.50 dB
Explanation:
Determine the minimum voltage gain
amplitude of input signal ( Vi ) = 15 mV
amplitude of output signal ( Vo) = 2 V
Vo = 2 v
therefore ; minimum gain = Vo / Vi = 2 / ( 15 * 10^-3 )
= 133.33
Minimum gain in DB = 20 log ( 133.33 )
= 42.498 ≈ 42.50 dB
Answer:
(d) 2 pF
Explanation: the charge on capacitor is given by the expression
Q=CV
where Q=charge
C=capacitance
V=voltage across the plate of the capacitor
here we have given Q=500 pF, V=250 volt
using this formula C=
=500×
×
=2×
=2 pF
Relay contacts that are defined as being normally open (n.o.) have contacts that are open only if the relay coil is known to have de-energized.
<h3>What is meant by normally open contacts?</h3>
Normally open (NO) are known to be open if there is no measure of current that is flowing through a given coil but it often close as soon as the coil is said to be energized.
Note that Normally closed (NO) contacts are said to be closed only if the coil is said to be de-energized and open only if the coil is said to carry current or is known to have energized.
The role of relay contact is wide. The Relays are tools that are often used in the work of switching of control circuits and it is one that a person cannot used for power switching that has relatively bigger ampacity.
Therefore, Relay contacts that are defined as being normally open (n.o.) have contacts that are open only if the relay coil is known to have de-energized.
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ANSWER</h2><h2>
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I had a couple of answers for this, but when I checked nothing
was right, so im not sure.
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