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3 years ago

15

A group of electrons is treated as a point charge of -1.12 x 10-18 C. How many electrons make up this point charge? Remember tha

t each electron has a charge of -1.602 x 10-19 C. o 2 o 4 4 07

1 answer:

Pepsi [2]3 years ago

4 0

Answer:

7

Explanation:

Given that the total charge is given by;

C =nq

Where;

n = number of charges

q = quantity of charge

Where the total amount of charge is -1.12 x 10-18 C and the magnitude of each charge is -1.602 x 10-19 C

Then the number of electrons is obtained from;

n = -1.12 x 10-18 C/ -1.602 x 10-19 C

n = 7

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And with solution...

Tems11 [23]

Answer:

The answer to your question is: V = 6.93 L

Explanation:

Data

N₂ = 5.6 g

Volume of NH₃ = ?

14 g of N ---------------- 1 mol

5.6 g ----------------------- x

x = (5.6 x 1) / 14 = 0.4 mol of N

Reaction

N₂ + 3H₂ ⇒ 2NH₃

1 mol of N₂ ---------------- 2 moles of NH₃

0.4 mol of N₂ -------------- x

x = (0.4 x 2) / 1

x = 0.8 mol of NH₃

Formula

PV = nRT

P = 5200 torr = 6.84 atm

V = ?

n = 0.8

R = 0.082 atm L/ mol °K

T = 450°C = 723°K

Substitution

V = (0.8)(0.082)(723) / 6.84

V = 6.93 L

7 0

3 years ago

Oksi-84 [34.3K]

Your question has been heard loud and clear.

Both scientific laws and scientific theories are not based on hypothesis.

Because , scientific laws are proven and so they are real not hypothetical.

Whereas scientifc theories can be hypothetical.

Thank you

4 0

3 years ago

If 50% of a radioactive element remains after 4000 years, what is the half-life?

ANTONII [103]

Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

If 50%, or half, of the element remains after 4000 years, that means the half life must be 4000 years.

Hope this helps!

4 0

3 years ago

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$

(2) $XCl_4(s)\rightarrow X(s)+2Cl_2(g)$ $\Delta H_2=-461.9kJ$

(3) $2H_2(g)+2Cl_2(g)\rightarrow 4HCl(g)$ $\Delta H_3=4\times -92.3kJ=-369.2kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $2H_2O(l)\rightarrow 2H_2O(g)$ $\Delta H_5=2\times 44.0kJ=88.0kJ$

The expression for enthalpy of main reaction will be:

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4+\Delta H_5$

$\Delta H=(483.6)+(-461.9)+(-369.2)+(-789.1)+(88.0)$

$\Delta H=-1048.6kJ$

Therefore, the enthalpy of the given reaction will be, -1048.6 kJ

4 0

3 years ago

Out of magnesium and Calcium which element is more reactive give reason

SIZIF [17.4K]

Answer:

Calcium is more reactive.

Explanation:

It is higher in the reactivity series, and contains more energy levels.

5 0

3 years ago