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Furkat [3]
2 years ago
15

6.0 mol NaOH reacts with

Chemistry
1 answer:
kodGreya [7K]2 years ago
7 0

2 moles of Na3PO4 form from 6.0 mol NaOH. Details about stoichiometry can be found below.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated stoichiometrically as follows:

3NaOH + H3PO4 → 3H₂O + Na3PO4

According to this equation,

3 moles of NaOH produces 1 mole of Na3PO4

This means that 6 moles of NaOH will produce 6/3 = 2 moles of Na3PO4

Therefore, 2 moles of Na3PO4 form from 6.0 mol NaOH.

Learn more about stoichiometry at: brainly.com/question/9743981

#SPJ1

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The CRC Handbook, a large reference book of chemical and physical data, lists two isotopes of indium (). The atomic mass of 4.28
ivanzaharov [21]

<u>Answer:</u> The mass of second isotope of indium is 114.904 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

  .....(1)

Let the mass of isotope 2 of indium be 'x'

  • <u>For isotope 1:</u>

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

  • <u>For isotope 2:</u>

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu

Hence, the mass of second isotope of indium is 114.904 amu

4 0
3 years ago
How many moles are in 4.818 x 1024 chloride ions
erastovalidia [21]

Answer:

<h3>The answer is 8.00 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{4.818 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 8.00332225...

We have the final answer as

<h3>8.00 moles</h3>

Hope this helps you

4 0
3 years ago
The partial pressure of hellium gas in a gaseous mixture of hellium and hydrogen is<br>​
RUDIKE [14]

Answer:

The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.

Hope this Helps (✿◡‿◡)

8 0
3 years ago
Which of the following would most likely be found in the outer cloud<br> region?
Likurg_2 [28]

Answer:

there is no "following". if you can attach an image for me, ill be glad to help.

Explanation:

have a good day,

~evita

6 0
3 years ago
Which of the following should be classified as a mixture? water air iron helium
Evgesh-ka [11]
Air is a mixture because it is made up of many constituents like oxygen, argon etc. it can be physically separated by fractional distillation. it doesnt have a formula unlike compounds and elements. its composition varies differently with its constituents.
5 0
3 years ago
Read 2 more answers
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