Answer:
The answer to your question is False.
Explanation:
Data
1 mole of NH₄NO₃
0.75 moles of N₂O
Percent yield = 25%
Chemical reaction
NH₄NO₃ ⇒ N₂O + 2H₂O
Process
1.- Determine the theoretical yield
1 mol NH₄NO₃ ------------- 1 mol of N₂O
2.- Calculate the percent yield
Percent yield = Actual yield / Theoretical yield x 100
-Substitution
Percent yield = 0.75 / 1 x 100
-Simplification
Percent yield = 0.75 x 100
-Result
Percent yield = 75%
Conclusion
False, the actual percent yield is 75%
Third quarter (or last quarter)
Elements in the same group tend to have very similar properties (D). This is due to the number of valence electrons each group has.
Answer:
305 litres of NO gas will be produced from 916 L of NO₂
Explanation:
Given the balanced equation of the chemical reaction as follows:
3 NO₂ (g) + H₂O( l) —— 2 HNO₃ (l) + NO (g)
Under standard conditions, 3 moles of No₂ will react with 1 mole of water to produce 1 mole of NO gas.
Molar volume of a gas at STP is 22.4 L
Number of moles of NO₂ gas present in 916 L = 916/22.4 = 40.893 moles of NO₂ gas
From the mole ratio of NO₂ to NO in the equation of reaction,
Number of moles of NO that will be produced = 1/3 × 40.893 moles = 13.631 moles of NO gas
Volume of 13.631 moles of NO gas = 13.631 × 22.4
Volume of NO gas produced = 305.334L
Therefore, Volume of NO gas produced from the reaction of 916 L of NO₂ with water = 305 L
2.998e^8 is how I would write it. If you want it with the least amount of decimals, use 3e^8
