M(P)=3.72 g
M(P)=31 g/mol
m(Cl)=21.28 g
M(Cl)=35.5 g/mol
n(P)=m(P)/M(P)
n(P)=3.72/31=0.12 mol
n(Cl)=m(Cl)/M(Cl)
n(Cl)=21.28/35.5=0.60 mol
P : Cl = 0.12 : 0.60 = 1 : 5
PCl₅ - is the empirical formula
A million years old
Duhhhh
The correct option is D. 0.2 M CaCl2 is has the lowest freezing point.
<h3>What is aqueous solution?</h3>
When one significance liquefies into another, a solution is formed. A solution is a homogenous mixture consisting of a solute dissolved into a solvent. The solute is the essence that is being dissolved, while the solvent is the dissolving medium. Solutions can be formed with multiple different classifications and forms of solutes and solvents. In this branch, we will focus on a resolution where the solvent is water.
- An aqueous solution is a moisture that contains one or more dissolved essence. The dissolved importance in an aqueous solution may be solids, gases, or different liquids.
- In directive to be a true solution, an assortment must be stable. When sugar is fully dissolved into moisture, it can stand for an undetermined amount of time, and the sugar will not recompense out of the solution. Further, if the sugar-water solution is passed through a filter, it will stay with the water.
- This is because the liquefied particles in a resolution are very small, usually less than 1nm in diameter. Solute particles can be atoms, ions, or molecules, counting on the type of essence that has been dissolved.
To learn more about aqueous solution, refer to:
brainly.com/question/14469428
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Answer:
group 1, 2 and 3 tend to get rid of electrons and start to form compounds with groups 7, 6, and 5.
Explanation:
Answer:
3.01 × 10²³ atoms Ne
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Tables
- Moles
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
<em>Identify</em>
[Given] 10.1 g Ne
[Solve] atoms Ne
<u>Step 2: Identify Conversions</u>
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
[PT] Molar Mass of Ne: 20.18 g/mol\
<u>Step 3: Convert</u>
- [DA] Set up:
![\displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})](https://tex.z-dn.net/?f=%5Cdisplaystyle%2010.1%20%5C%20g%20%5C%20Ne%28%5Cfrac%7B1%20%5C%20mol%20%5C%20Ne%7D%7B20.18%20%5C%20g%20%5C%20Ne%7D%29%28%5Cfrac%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Ne%7D%7B1%20%5C%20mol%20%5C%20Ne%7D%29)
- [DA] Divide/Multiply [Cancel out units]:
![\displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne](https://tex.z-dn.net/?f=%5Cdisplaystyle%203.01398%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Ne)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne