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OleMash [197]
2 years ago
13

What is observed that connects radio emissions in the galactic nucleus with the emissions in the halo or radio lobes?

Physics
1 answer:
Licemer1 [7]2 years ago
5 0

Answer:

What is observed that connects radio emissions in the galactic nucleus with the emissions in the halo or radio lobes? There is a jet of matter coming out of the nucleus, which often points toward the lobes.

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Waves are observed passing under a dock. Wave crests are 8.0 meters apart. The time for a complete wave to pass by is 4.0 second
Debora [2.8K]
<h3><u>Answer;</u></h3>

The period of the wave is <u><em>4 seconds</em></u>

<h3><em><u>Explanation;</u></em></h3>
  • <em><u>The period of a wave or periodic time is the time taken for one complete oscillation to occur.</u></em> In this case, one complete oscillation occurs when the wave moves from one crest to the next or a trough to the next. <em><u>This takes 4 seconds. Therefore the period is 4 seconds.</u></em>
  • <em><u>Frequency on the other hand is the number of oscillations by a wave in one second. Thus, f = 1/T, that is frequency is the reciprocal of periodic time.</u></em>
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3 years ago
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Describe a solar eclipse. Be sure to include the positions of the sun, moon, and earth.
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It’s the type of eclipse that occurred when the moon passes between the sun and earth, and when the moon fully or partially blocks the sun.
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a 70 kg man standing on ice throws a 3 kg body horizontally at 8 m/s. the friction coefficient between the ice and his feet is 0
GalinKa [24]

The distance at which the man slips is 0.3 m

Newton's Second Law, F = ma, is used to calculate the braking distance. By dividing the mass of the car by the gravitational acceleration, one may determine its weight. The weight of the car multiplied by the coefficient of friction equals the brake force.

Given-

mass of man= 70 kg

frictional coefficient μ=0.02

mass of body thrown= m2 = 3kg

let s be the stopping distance

we know that frictional force = F= μN

=μMg= 0.02 x 70 x 10

=14 N

∴acceleration, a= 14/70 = 0.2 m/s²

now on applying conservation of linear momentum

pi=pf            pi=0 (initially at rest)

0=m1v1-m2v2 (v1= velocity of man) (v2=velocity of body= 8m/s

v1= m2v2 /m1= 0.3 m/s

we know,

v²- u² = -2as

0- (0.3) ²= -2 x 0.2 x 5

s= 0.09/0.4 ≈ 0.3 m

Learn more about distance here-

brainly.com/question/15172156

#SPJ4

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A decrease in mass will decrease an objects weight because 
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Which property of light remains unchanged when it enters a different medium?
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