Two forces F1=20N and F2=30N are acting on an object as shown in figure: F1=20N F2=30N (i) Find the net force acting on the obje
1 answer:
The net force is the 10N force and its direction is towards F2 force.
<h3>What is resultant force?</h3>The resultant force or the net force is the actual force that acts on a body. We are told that the two forces act in opposite directions hence the net force is F2 - F1 = 30 N - 20 N = 10 N.
ii) The direction of this net force is going to be towards the 30N force.
iii) If the body does not move under the application of these forces then the F1 force must be reinforced by another force which balances it against the F2 force.
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a)
b)
c)
d) (radians)
Explanation:
a)
The motion of the cup sliding off the counter is the motion of a projectile, consisting of two independent motions:
- A uniform motion along the horizontal direction
- A uniformly accelerated motion (free fall) along the vertical direction
The time of flight of the cup is entirely determined by the vertical motion, therefore we can use the suvat equation:
where here:
(the vertical displacement is the height of the counter)
(the initial vertical velocity of the cup is zero)
(the vertical acceleration is the acceleration of gravity)
Solving for t, we find the time of flight of the cup:
b)
To solve this part, we just analyze the horizontal motion of the cup.
Here we know that the horizontal motion of the cup is uniform: this means that is horizontal speed is constant during the whole motion, and it is actually equal to the speed at which the mug leaves the counter.
For a uniform motion, the speed is given by
where
d is the distance covered
t is the time taken
Here, the distance covered is , the distance from the base of the counter, while the time taken is the time of flight:
Substituting into the previous equation, we find the speed of the mug as it leaves the counter:
c)
Here we want to find the speed of the cup immediately before it hits the floor.
Here we have to consider that while the mug falls, its vertical speed increases, while the horizontal speed remains constant.
Therefore, the horizontal speed of the cup before it hits the ground is:
The vertical speed instead is given by the suvat equation:
where:
is the initial vertical velocity
is the acceleration
is the time of flight
Substituting,
The actual speed of the cup just before it hits the floor is the resultant of the horizontal and vertical speeds, so it is:
d)
Just before hitting the floor, the velocity of the cup has two components:
is the horizontal component (in the forward direction)
is the vertical component (in the downward direction)
Since the two components are perpendicular to each other, the angle of the direction is given by the equation
where here is measured as below the horizontal direction.
Substituting the expressions for , we find:
So
(radians)