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shusha [124]
3 years ago
8

Which organ serves as the primary site of amino acid metabolism (i.e. oxidation, transamination, deamination, gluconeogenesis, e

tc.)?
Chemistry
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:

The liver

Explanation:

The liver -

In human beings the location of liver is just in the upper right portion of the abdomen , exactly below the diaphragm .

Liver is present in specifically vertebrates , and is responsible for various metabolism , like producing hormones , decomposition of the red blood cells , regulating the storage of glycogen and the synthesis of proteins .

Liver is the main site for the process of gluconeogenesis , amino acid catabolism .

Liver is the very organ , that has full urea cycle .

Hence , from the given information of the question ,

The correct term is the liver .

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If an atom of an element has a mass number of 45 and it has 20 neutrons in its nucleus, what is the atomic number of the
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How is the mass in grams of the element converted to amount in atoms
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A substance's molar mass is calculated by multiplying its relative atomic mass by the molar mass constant (1 g/mol). ... By multiplying a given mass by the molar mass, the amount of moles of the substance can be calculated.
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Compare rutherford's expected outcome of the gold-foil experiment with the actual outcome.
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6 0
3 years ago
How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m
Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})  

pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of acetic acid = 4.74

[CH_3COONa]=?mol  

[CH_3COOH]=0.200mol

pH = 5.00

Putting values in above equation, we get:

5=4.74+\log(\frac{[CH_3COONa]}{0.200})

[CH_3COONa]=0.364mol

To calculate the mass of sodium acetate for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0
3 years ago
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