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shusha [124]
4 years ago
8

Which organ serves as the primary site of amino acid metabolism (i.e. oxidation, transamination, deamination, gluconeogenesis, e

tc.)?
Chemistry
1 answer:
GarryVolchara [31]4 years ago
5 0

Answer:

The liver

Explanation:

The liver -

In human beings the location of liver is just in the upper right portion of the abdomen , exactly below the diaphragm .

Liver is present in specifically vertebrates , and is responsible for various metabolism , like producing hormones , decomposition of the red blood cells , regulating the storage of glycogen and the synthesis of proteins .

Liver is the main site for the process of gluconeogenesis , amino acid catabolism .

Liver is the very organ , that has full urea cycle .

Hence , from the given information of the question ,

The correct term is the liver .

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What is the mole, and why is it useful in chemistry?
Snowcat [4.5K]

Answer:The mole is important because it allows chemists to work with the subatomic world with macro world units and amounts. Atoms, molecules and formula units are very small and very difficult to work with usually. However, the mole allows a chemist to work with amounts large enough to use.

Explanation:

6 0
4 years ago
Which one of the following species is diamagnetic: a. F b. Zn2+ C. Cu2+ d. Ca+​
diamong [38]

Answer:

The correct answer to this question is C

Explanation:

3 0
3 years ago
The partial pressure of O2 in air at sea level is 0.21atm. The solubility of O2 in water at 20∘C, with 1 atm O2 pressure is 1.38
adell [148]

Answer:

1.21x10^{-3} M

Explanation:

Henry's law relational the partial pressure and the concentration of a gas, which is its solubility. So, at the sea level, the total pressure of the air is 1 atm, and the partial pressure of O2 is 0.21 atm. So 21% of the air is O2.

Partial pressure = Henry's constant x molar concentration

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H = \frac{0.21}{1.38x10^{-3} }

H = 152.17 atm/M

For a pressure of 665 torr, knowing that 1 atm = 760 torr, so 665 tor = 0.875 atm, the ar concentration is the same, so 21% is O2, and the partial pressure of O2 must be:

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P = Hx[O2]

0.1837 = 152.17x[O2]

[O2] = 0.1837/15.17

[O2] = 1.21x10^{-3} M

7 0
4 years ago
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b

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3 0
3 years ago
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