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GREYUIT [131]
3 years ago
11

Water is poured into a container that has a leak.The

Physics
1 answer:
kotykmax [81]3 years ago
5 0
I calculated on a sheet and used differentiation to solve the problems.

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How does the science of heat transfer differ from the science of thermodynamics?
mariarad [96]

Answer:

The science of thermodynamics deals with the fundamental laws that guide how physical processes occur in relation with the energy transfer. When a system or process changes from one state of equilibrium to another, thermodynamics is interested with the amount of heat transfer during the process. On the other hand, the science of heat transfer is simply about the rate of heat and temperature distribution inside a system at a particular point in time.

Explanation:

3 0
3 years ago
A particular frost-free refrigerator uses about 710kWh of electrical energy per year. Express this amount of energy in J, kJ, &a
Dafna11 [192]
<span>A particular frost-free refrigerator uses about 710kWh of electrical energy per year. You are to express this amount of energy in J, kJ, & Calories. 

1 year (365 days / 1 year)(24 hours / 1 day)(3600s / 1h) = 31,536,000s

710 kWh/yr (1 yr) = 710 kWh
710 x 10^3 Wh = </span>710 x 10^3(J/s)(31,536,000s)<span> = 2.24 x 10^13 J
</span>2.24 x 10^13 J = 2.24 x 10^10 kJ = 5.35 x 10^12 cal
6 0
3 years ago
Read 2 more answers
The density of air is 1.3 kg/m^3. What mass of air is contained in a room measuring 2.5m x 4m x 10m? Give your answer in kg. Bra
krek1111 [17]
Mass= density x volume
1.3 kg/m^3 x ( 2.5x4x10) m^3
= 130 kg
7 0
3 years ago
A power supply is connected to a 59 Ohm resistor and a 53 Ohm resistor in series. The total current is found to be 0.15 A. What
kirill [66]

the answer is 47265.dug

Explanation:

im bot sure

4 0
2 years ago
6. A 2-kg ball B is traveling around in a circle of radius r1 = 1 m with a speed (vB)1 = 2 m/s. If the attached cord is pulled d
kipiarov [429]

Answer:

Explanation:

Given that,

Mass of ball m = 2kg

Ball traveling a radius of r1= 1m.

Speed of ball is Vb = 2m/s

Attached cord pulled down at a speed of Vr = 0.5m/s

Final speed V = 4m/s

Let find the transverse component of the final speed using

V² = Vr²+ Vθ²

4² = 0.5² + Vθ²

Vθ² = 4²—0.5²

Vθ² = 15.75

Vθ =√15.75

Vθ = 3.97 m/s.

Using the conservation of angular momentum,

(HA)1 = (HA)2

Mb • Vb • r1 = Mb • Vθ • r2

Mb cancels out

Vb • r1 = Vθ • r2

2 × 1 = 3.97 × r2

r2 = 2/3.97

r2 = 0.504m

The distance r2 to the hole for the ball to reach a maximum speed of 4m/s is 0.504m

The required time,

Using equation of motion

V = ∆r/t

Then,

t = ∆r/Vr

t = (r1—r2) / Vr

t = (1—0.504) / 0.5

t = 0.496/0.5

t = 0.992 second

7 0
3 years ago
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