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dexar [7]
3 years ago
6

A force of 45 newtons is applied on an object, moving it 12 meters away in the same direction as the force. What is the magnitud

e of work done on the object by this force? Part A: Enter the variable symbol for the quantity you need to find. Use your keyboard and the keypad to enter your answer. Then click Done.
Physics
1 answer:
NARA [144]3 years ago
6 0
<h2>Answer: 540 J</h2>

Explanation:

The Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  

Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (1)  

In this case both (the force and the distance in the path) are parallel (this means they are in the same direction), so the work W performed is the product of the force exerted to push the box F=45N by the distance traveled d=12m.

Hence:  

W=(45N)(12m)   (2)

W=540Nm=540J

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A variable is defined as anything that
LenKa [72]
Answer : Quantity or quality that varies like manipulating a variable to see what will happen to another variable
3 0
3 years ago
See the attachment included with this note
alexdok [17]

The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.

<h3>What is the angular velocity of the propeller?</h3>

The angular velocity of the propeller in rad/s is given as follows:

  • 1 rev/m = 2π/60 rad/s.

1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.

b. The linear velocity, v = radius * angular velocity

Linear velocity, v = 2.25/2 * 136.1

v = 153.1 m/s

c. Centripetal acceleration, a = \frac{v^{2}}{r}

a = \frac{(153.1)^{2}}{1.125} = 20835.2\:ms^{2}

Centripetal acceleration in terms of g; g = \frac{20835.2}{9.81} = 2123.8 g

Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.

Learn more about angular velocity and centripetal acceleration at: brainly.com/question/10703948

#SPJ1

7 0
1 year ago
The auditory canal behaves like a resonant tube to aid in hearing. One end terminated at the eardrum, while the other opens to t
kompoz [17]

Answer:

3.6 kHz

Explanation:

The pipes behave like a closed pipe . The end open is the end of the air canal outside the ear and the closed end is the eardrum.

The first harmonic will be as seen in the figure attached.

The length of the first harmonic will be λ/4.

λ/4=2.4 cm

λ=2.4 * 4=9.6 cm 0.096 m

Speed of Sound- 344 m/s(in air)

velocity(v) * Time Period(T) = Wavelength (λ)

Also, Time Period(T)= \frac{\textrm{1}}{\textrm{Frequency(f)}}

\frac{\textrm{Velocity}}{\textrm{Wavelength}}=\frac{\textrm{1}}{\textrm{Time Period}} =Frequency

Plugging in the values into the equation,

Frequency = \frac{344}{0.096} Hz

                  = 3583.3 Hz≈3600 Hz= 3.6 kHz

Frequency= 3.6 kHz

7 0
3 years ago
Read 2 more answers
While a constant total force of 17 n is exerted on a cart, the cart's acceleration is 5 m/s2. find the mass of the cart?
zaharov [31]
F = mass × acceleration
17 = mass × 5
mass = 17/5
6 0
3 years ago
Infer why the doppler effect can or can not occur in all waves.
Darya [45]

Answer:

it can occur in all waves because all wave have a frequency

8 0
2 years ago
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