Answer : Quantity or quality that varies like manipulating a variable to see what will happen to another variable
The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
<h3>What is the angular velocity of the propeller?</h3>
The angular velocity of the propeller in rad/s is given as follows:
1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.
b. The linear velocity, v = radius * angular velocity
Linear velocity, v = 2.25/2 * 136.1
v = 153.1 m/s
c. Centripetal acceleration, 

Centripetal acceleration in terms of g; 
Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
Learn more about angular velocity and centripetal acceleration at: brainly.com/question/10703948
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Answer:
3.6 kHz
Explanation:
The pipes behave like a closed pipe . The end open is the end of the air canal outside the ear and the closed end is the eardrum.
The first harmonic will be as seen in the figure attached.
The length of the first harmonic will be λ/4.
λ/4=2.4 cm
λ=2.4 * 4=9.6 cm 0.096 m
Speed of Sound- 344 m/s(in air)
velocity(v) * Time Period(T) = Wavelength (λ)
Also, Time Period(T)= \frac{\textrm{1}}{\textrm{Frequency(f)}}
\frac{\textrm{Velocity}}{\textrm{Wavelength}}=\frac{\textrm{1}}{\textrm{Time Period}} =Frequency
Plugging in the values into the equation,
Frequency =
Hz
= 3583.3 Hz≈3600 Hz= 3.6 kHz
Frequency= 3.6 kHz
F = mass × acceleration
17 = mass × 5
mass = 17/5
Answer:
it can occur in all waves because all wave have a frequency