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Alex_Xolod [135]
2 years ago
7

Use the graph below to answer the following question. Observe the ionization energy needed to remove the 10th and 11th electrons

. What does this indicate?
Chemistry
1 answer:
natta225 [31]2 years ago
7 0

The ionization energy will increase substantially when 11th electron is removed compared to when the 10th electron is removed.

<h3>What is ionization energy?</h3>

Ionization energy is the energy required to remove one or more electrons from a neutral atom in its gaseous state to form a positively-charged ion.

The ionization energy increases steadily as successive electrons are removed from an atom. A substantial increase in ionization energy occurs with the removal of an electron from a filled inner shell.

The 10th electrons is the last electron in the L shell of atoms. The 11th electron is the first electron in a  filled inner shell.

Therefore, ionization energy will increase substantially when 11th electron is removed compared to when the 10th electron is removed.

Note that there was no attached graph and the answer was given based on the general trend observed in ionization energies.

Learn more about ionization energy at: brainly.com/question/1445179

#SPJ1

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A sample of potassium nitrate (49.0 g) is dissolved in 101 g of water at 100 °C, with precautions taken to avoid evaporation of
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Answer:

Saturated solution

Explanation:

Saturated solution is the solution in which no more solute can be dissolved at a particular temperature.

A amount of the solute, potassium nitrate is dissolved at elevated temperature and on cooling, it precipitates. It means that the solution is saturated at that temperature. <u>Precipitation of the solute at lower temperature indicates that the solution is saturated solution.</u>

8 0
4 years ago
The table shows the amount of radioactive element remaining in a sample over a period of time.
Lunna [17]

Answer:

1. The half-life is 22 years.

2. 132 years

Explanation:

1. Determination of the the half-life.

The half-life of an element is the time taken for half the element to decay.

From the table given above, the original amount of the element 45 g. If we divide 45 by 2, we'll have 22.5 g as half the original amount of element.

Now, the time taken to obtain 22.5 g as shown from the table is 22 years.

Thus, the half-life the element is 22 years.

2. Determination of the time.

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Time (t) =?

Next, we shall the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

4.8125 = 1/2ⁿ × 308

Cross multiply

4.8125 × 2ⁿ = 308

Divide both side by 4.8125

2ⁿ = 308 / 4.8125

2ⁿ = 64

Express 64 in index form with 2 as the base.

2ⁿ = 2⁶

n = 6

Thus, 6 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Number of half-lives (n) = 6

Half-life (t½) = 22 years

Time (t) =?

n = t / t½

6= t / 22 years

Cross multiply

t = 6 ×22

t = 132 years.

Thus, the time taken is 132 years.

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3 years ago
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Calculate the enthalpy of combustion, δh∘comb, for c6h14. you'll first need to determine the balanced chemical equation for the
Vedmedyk [2.9K]
<span>Answer: Enthalpy Change = (6 x -393.5) + (7 x -285.8) - (-204.6) + (19/2) 0.....??? like.. (6 x Enth CO2) + ( 7 x Enth H2O) - (Enth C6H14) + (19/2) Enth O2</span>
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4 years ago
Carbon-12 and carbon-13 are isotopes of carbon.
ohaa [14]

Answer:

Isotopes of an element share the same number of protons but have different numbers of neutrons. Let's use carbon as an example. There are three isotopes of carbon found in nature – carbon-12, carbon-13, and carbon-14. All three have six protons, but their neutron numbers - 6, 7, and 8, respectively - all differ.

Explanation:

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3 years ago
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