Answer:
I think is A 690 nm or c 500 nm
In order to balance this equation you need to count each element and how many of the individual elements are in the equation. _H2+N2=2 NH3 You multiply the 2 (Which is the coefficient) by the 3 (which is the subscript) This would equal 6 which indicated there are 6 hydrogen atoms on the right side so the left side should also have 6 hydrogen atoms
The missing coefficient on the left side must multiple the 2 to become 6 hydrogen Answer=3
Answer:
![\large\boxed{\text{0.512 V}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Ctext%7B0.512%20V%7D%7D)
Explanation:
We must use the Nernst equation
![E = E^{\circ} - \dfrac{RT}{zF}lnQ](https://tex.z-dn.net/?f=E%20%3D%20E%5E%7B%5Ccirc%7D%20-%20%5Cdfrac%7BRT%7D%7BzF%7DlnQ)
The equation for the cell reaction is is
2Cl⁻(0.384 mol·L⁻¹) + 2Co³⁺(0.324 mol·L⁻¹) ⇌ Cl₂(5.80 atm) + 2Co²⁺(0.158 mol/L)
Data:
E° = 0.483 V
R = 8.314 J·K⁻¹mol⁻¹
T = 25 °C
n = 2
F = 96 485 C/mol
Calculation:
T = 25 + 273.15 = 298.15 K
![Q = \dfrac{\text{[Cl}^{-}]^{2}[\text{Co}^{3+}]^{2}}{p_{\text{Cl}_{2}}^{2}\text{[Co}^{3+}]^{2}} = \dfrac{0.384^{2} \times 0.324^{2}}{5.80 \times 0.158^{2}} =0.1069\\\\E = 0.483 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln(0.1069)\\\\=0.483 -0.01285 \times (-2.236) = 0.483 + 0.02872 = \textbf{0.512 V}\\\text{The cell potential is } \large\boxed{\textbf{0.512 V}}](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BCl%7D%5E%7B-%7D%5D%5E%7B2%7D%5B%5Ctext%7BCo%7D%5E%7B3%2B%7D%5D%5E%7B2%7D%7D%7Bp_%7B%5Ctext%7BCl%7D_%7B2%7D%7D%5E%7B2%7D%5Ctext%7B%5BCo%7D%5E%7B3%2B%7D%5D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B0.384%5E%7B2%7D%20%5Ctimes%200.324%5E%7B2%7D%7D%7B5.80%20%5Ctimes%200.158%5E%7B2%7D%7D%20%3D0.1069%5C%5C%5C%5CE%20%3D%200.483%20-%20%5Cleft%20%28%5Cdfrac%7B8.314%20%5Ctimes%20298.15%20%7D%7B2%20%5Ctimes%2096485%7D%5Cright%20%29%20%5Cln%280.1069%29%5C%5C%5C%5C%3D0.483%20-0.01285%20%5Ctimes%20%28-2.236%29%20%3D%200.483%20%2B%200.02872%20%3D%20%5Ctextbf%7B0.512%20V%7D%5C%5C%5Ctext%7BThe%20cell%20potential%20is%20%7D%20%5Clarge%5Cboxed%7B%5Ctextbf%7B0.512%20V%7D%7D)
Answer:
3rd response
4th response
Explanation:
i lowkey feel like im doing this whole chem exam for u lol. good luck anyway! u rock!