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1 year ago

Please provide thorough explanation

Chemistry

1 answer:

Arlecino [84]1 year ago

4 0

Possible products in this reaction are the products 2 and 3.

<h3>What is the Friedel Crafts reaction?</h3>

The Friedel Crafts reaction is one in which the electrophile is created by a Lewis acid reaction between the AlCl3 and the alkylhalide reactant .

Now we know that there is the possibility of two products in this reaction due to a resonance shift as such possible products in this reaction are the products 2 and 3.

Learn more about Friedel Crafts reaction:brainly.com/question/14993566?

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Fran hangs three balloons from strings. She gives the first balloon a positive charge. She gives the second balloon a negative c

fgiga [73]

Explanation: We are given three balloon carrying different charges: One having positive charge, one having negative charge and one having no charge.

When we bring positive rod near these three balloons, all of them behave differently.

According to the Coulomb's Law:

Like charges repel each other and unlike charges attract each other.

When we bring positive rod towards the balloon having positive charge, the balloon will move away from the rod, because like charges repel each other.

When we bring positive rod near negative balloon, the balloon will be attracted to the rod because unlike charges attract each other.

But, when we bring positive rod towards the balloon having no charge, the charges will be induced in the balloon. Although the balloon is neutral in nature but it will still carry some +ve or -ve charges. So, when the positive rod is bought near neutral ball, the negative side of the balloon will get attracted towards the rod and positive side will be repelled. From this, we say that the rod has induced some charges in the balloon.

5 0

3 years ago

Sort these six events from the earliest to the most recent. 1. Democritus proposes the existence of atoms 3rd 2. Dalton's atomic

Nitella [24]

Explanation:

1. Democritus proposes the existence of atoms

2. Dalton's atomic theory

3. J. J. Thomson discovers the electron

4. Rutherford's gold foil experiment

5. Bohr model

6. Schrödinger's Wave Mechanics model of the atom

The first idea about matter containing atoms dates back to Greek philosophers. One of them was Democritus .

In 1808 Dalton put forward his atomic theory

In 1897 J.J Thomson discovered cathode rays using his gas discharge tube experiment.

In 1911, Ernest Rutherford proposed the nuclear model of the atom using experiments on the gold foil.

Neils Bohr in 1913 suggested his own atomic model

Erwin Schrodinger formulated the wave equation of electrons

Learn more;

Dalton atomic theory brainly.com/question/1979129

Rutherford gold foil experiment brainly.com/question/1859083

#learnwithBrainly

4 0

3 years ago

The four rows of data below show the boiling points for a solution with no solute, sucrose (C12H22O11), sodium chloride (NaCl),

choli [55]

Answer:

The four rows of data below show the boiling points for a solution with no solute, sucrose (C12H22O11), sodium chloride (NaCl), and calcium chloride (CaCl2) (not in that order). Which boiling point corresponds to calcium chloride?

A. 101.53° C

B. 100.00° C

C. 101.02° C

D. 100.51° C

Which of the following solutions will have the lowest freezing point?

A. 1.0 mol/kg sucrose (C12H22O11)

B. 1.0 mol/kg lithium chloride (LiCl)

C. 1.0 mol/kg sodium phosphide (Na3P)

D. 1.0 mol/kg magnesium fluoride (MgF2)

Which of the following compounds will be most effective in melting the ice on the roads when the air temperature is below zero?

A. sodium iodide (NaI)

B. magnesium sulfate (MgSO4)

C. potassium bromide (KBr)

D. All will be equally effective.

Four different solutions have the following vapor pressures at 100°C. Which solution will have the greatest boiling point?

A. 98.7 kPa

B. 96.3 kPa

C. 101.3 kPa

D. 100.2 kPa

Four different solutions have the following boiling points. Which boiling point corresponds to a solution with the lowest freezing point?

A. 101.2°C

B. 105.9°C

C. 102.7°C

D. 108.1°C

Explanation:

The following are the answers to the different questions:

A. 101.53° C

Which of the following solutions will have the lowest freezing point?

D. 1.0 mol/kg magnesium fluoride (MgF2)

Which of the following compounds will be most effective in melting the ice on the roads when the air temperature is below zero?

A. sodium iodide (NaI)

Four different solutions have the following vapor pressures at 100°C. Which solution will have the greatest boiling point?

B. 96.3 kPa

Four different solutions have the following boiling points. Which boiling point corresponds to a solution with the lowest freezing point?

D. 108.1°C

5 0

3 years ago

What is The pH and pOH of a 1.00x10-3M solution of CH3COOH (Ka=1.75x10-5) ?

zaharov [31]

Answer:

Explanation:

Since $CH _ 3COOH$ is a weak acid to find the pH of $CH _ 3COOH$ we use the formula

$pH = - \frac{1}{2} log(Ka) - \frac{1}{2} log(c)$

where

Ka is the acid dissociation constant

c is the concentration

From the question

Ka of $CH _ 3COOH$ = 1.75 × 10^-5

c = 1.00 × 10-³M

Substitute the values into the above formula and solve for the pH

That's

$pH = \frac{1}{2} ( - log(1.75 \times {10 }^{ - 5} - log(1.00 \times {10}^{ - 3} ) ) \\ = \frac{1}{2} (4.757 + 3) \\ = \frac{1}{2} \times 7.757) \\ = 3.8785 \: \: \: \: \: \: \: \:$

We have the answer as

To find the pOH we use the formula

pH + pOH = 14

pOH = 14 - pH

pOH = 14 - 3.9

We have the answer as

Hope this helps you

4 0

3 years ago

Calculate the number of moles of sulfuric acid in the total volume you used in the lab (i.e., 8.00 mL). Hint: Use the methodolog

insens350 [35]

Answer:

0.147 mol

Explanation:

Step 1: Calculate the volumetric concentration (Cv)

We will use the following expression.

Cv = Cg × ρ

Cv = 98.0 g%g × 1.84 g/mL = 180 g%mL

Step 2: Calculate the molarity of sulfuric acid

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

M = 180 g / 98.08 g/mol × 0.100 L = 18.4 M

Step 3: Calculate the moles of solute in 8.00 mL of solution

8.00 × 10⁻³ L × 18.4 mol/L = 0.147 mol

4 0

2 years ago