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Delvig [45]
3 years ago
11

A cheetah runs with a positive acceleration. What does this tell you about the velocity time graph for the cheetah?

Physics
1 answer:
Katarina [22]3 years ago
3 0
B is the correct answer
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He vector parts that add up to the resultant are called ____.
cupoosta [38]

1. Answer: components

A two dimensional vector can be divided into two parts called horizontal component and vertical component.

A three dimensional vector can be divided into three components: one along x-axis, one along y-axis and one along z-axis.

Hence, the vector parts that add up to the resultant are called components.

2. Answer: 5 miles.

The resultant distance along the straight line from the starting point to the end point would be the displacement.

The displacement would be equal to the magnitude of the hypotenuse formed in the right triangle.

Displacement, d=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5 miles

3. Answer: Scalar

A scalar quantity has only magnitude. For example, speed and distance are scalar quantities and can be normally added to find the total.

A vector quantity has both magnitude as well as direction. The components are summed according to vector addition rules. For example, velocity, acceleration, force etc.

5 0
3 years ago
A pendulum has 844 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
Stolb23 [73]
844J.
Assuming that there were no encumbrances during it's foreswing and it reached it's full potential at apogee.
8 0
3 years ago
A girl coasts down a hill on a sled, reaching level ground at the bottom with a speed of 7.4 m/s. The coefficient of kinetic fri
Amanda [17]

Answer: 62.22 meters

Explanation:

Two solve this, we need to know first how the Sled interact with the snow. While the Sled runs over the snow, the snow opposes to it movement, this is call friction. Frictions creates is a force that goes against any movement and is caused by the interaction between surfaces.

Friction can be calculated using the following equation:

Friction's Force (Ff) = m*N

Where m is the Frictions coficient and N is call Normal, which is a force created by the contact between any weight and a surface. Because the sled is and the surface are totally horizontal, the Normal is equal to the Sled's Weight.

So for this case, we can calculate the Friction's Force:

Ff = 0.045 * 735 N

Ff = 33,07 N

This force will cause a negative acceleration the Sled causing it to slow down and finally stop. To know this accelaration we can use the following equation:

Force (F) = Mass (m) * Accelaration (a)

Looking for the accelaration:

Acceleration (a) = F / M

As a side note:

Mass (M) = F / a                                        (1)

Where we know that F is equal to our Friction Force (Ff) and the Mass for the girl and the Sled can be obtained using the previous equation (1) like this

Girl and sled Mass (M) = 735 N / (9.81 m/s)

M = 74,92 Kg

This is posible, because the Girl and The Sled are aplying a Force on the ground equal to 735 N. The accelartion for their mass is the gravity

Now, with the mass we can found the Accelaration caused by friction:

Acceleration (a) = Ff / M

Accelaration (a) = 33,07 N / 74,92 Kg

a = 0,44 m/s^{2}

To know how far the Sled travel we can use the following equation:

V_{f} ^{2} = V_{0} ^{2} + 2ax

Where Vf is the Final Velocity, which is when the sled finally stops (Vf = 0), Vo is the Initial Speed of the Sled equal to 7.4 m/s and a is equal to the negative accelaration that causes the friction.

(0)^{2} = (7.4 m/s)^{2} + 2(-0,44)x

Searching for x:

x = \frac{0 - (7.4 m/s)^{2} }{-0.88}

x = \frac{0 - (7.4 m/s)^{2} }{-0.88}

x = \frac{0 - (7.4 m/s)^{2} }{-0.88}

x = 62.22 meters

The girls will run over the snow 62.22 meter until finally stopping

4 0
3 years ago
A 2-kg wheel rolls down the road with a linear speed of 15m/s. Find its trwansitional and rotational kinetic energies.​
Elza [17]

Answer:

The translational kinetic energy is 225 J

The rotational kinetic energy is 225 J

Explanation:

Given;

mass of the wheel, m = 2-kg

linear speed of the wheel, v = 15 m/s

Transnational kinetic energy is calculated as;

E = ¹/₂MV²

where;

M is mass of the moving object

V is the velocity of the object

E =  ¹/₂ x 2 x (15)²

E = 225 J

Rotational kinetic energy is calculated as;

E = ¹/₂Iω²

where;

I is moment of inertia

ω is angular velocity

E = \frac{1}{2} I \omega^2\\\\E = \frac{1}{2} *mr^2*(\frac{v}{r})^2\\\\E =  \frac{1}{2} *mr^2*\frac{v^2}{r^2} \\\\E =  \frac{1}{2}mv^2

E =  ¹/₂ x 2 x (15)²

E = 225 J

Thus, the translational kinetic energy is equal to rotational kinetic energy

6 0
3 years ago
What is the change in momentum of a 0.18 kg arrow that is traveling at 100 m/s and is stopped by a hay
Kryger [21]
The 2 seconds part isn’t relèvent to the question.
So momentum = mass x velocity
So 0.18 x 100 = 18
3 0
3 years ago
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