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zloy xaker [14]
2 years ago
9

Nora's hair dryer is 64% efficient. If 1000 J of energy is supplied to the hair dryer, how much energy will it transfer usefully

to Nora's hair?
Physics
1 answer:
lakkis [162]2 years ago
6 0

Answer:

<em>The</em><em> </em><em>hair</em><em> dryer</em><em> will transfer 640J of </em><em>energy </em><em>usefully</em><em> </em><em>to </em><em>Nora’</em><em>s</em><em> </em><em>hair</em><em>.</em>

Explanation:

<em>Efficiency</em><em> </em><em>=</em><em> </em><em>ou</em><em>t</em><em>put/</em><em>input</em><em> </em><em>×</em><em> </em><em>100%</em>

<em>Data</em>

<em>Efficiency</em><em> </em><em>=</em><em> </em><em>6</em><em>4</em><em>%</em>

<em>Energy</em><em> </em><em>input</em><em> </em><em>=</em><em> </em><em>1000</em><em>J</em>

<em>Energy</em><em> </em><em>output</em><em> </em><em>=</em><em> </em><em>?</em>

<em>Efficiency</em><em> </em><em>=</em><em> </em><em>Energy</em><em> </em><em>output</em><em>/</em><em>Energy</em><em> </em><em>input</em><em> </em><em>×</em><em> </em><em>100%</em>

<em>6</em><em>4</em><em>%</em><em> </em><em>=</em><em> </em><em>E</em><em>nergy </em><em>output</em><em> </em><em>/</em><em>1000</em><em>J</em><em> </em><em>×</em><em> </em><em>100%</em>

<em>Divide</em><em> both</em><em> sides</em><em> </em><em>by </em><em>100%</em><em> </em>

<em>0</em><em>.</em><em>6</em><em>4</em><em> </em><em>=</em><em> </em><em>Energy</em><em> </em><em>output</em><em>/</em><em>1000</em><em>J</em>

<em>Energy</em><em> output</em><em> </em><em>=</em><em> </em><em>0</em><em>.</em><em>6</em><em>4</em><em> </em><em>×</em><em> </em><em>1000</em><em>J</em>

<em>Efficiency</em><em> </em><em>output</em><em> </em><em>=</em><em> </em><em>6</em><em>4</em><em>0</em><em>J</em>

<em>Therefore</em><em> </em><em>the</em><em> </em><em>hair</em><em> </em><em>dryer</em><em> </em><em>will</em><em> </em><em>transfer</em><em> </em><em>6</em><em>4</em><em>0</em><em>J</em><em> </em><em>of </em><em>energy</em><em> </em><em>usefully to Nora’s</em><em> </em><em>hair.</em>

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