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lidiya [134]
3 years ago
6

Magnitude is used to show the brightness of one object compared with the brightness of another object with the _____ magnitude o

f a star referring to a star's brightness as seen from your eyes and _____ magnitude being the actual brightness of a star.
Physics
1 answer:
Cloud [144]3 years ago
3 0

The <u>apparent magnitude</u> of a star refers to its brightness as seen from your eyes and <u>absolute magnitude</u> being the actual brightness of a star.

<h3>What is magnitude?</h3>

Magnitude can be defined as a unitless measure which is used to show the brightness of an object in comparison with the brightness of another object.

Basically, there are two types of magnitude and these include the following:

  • Apparent magnitude
  • Absolute magnitude

In conclusion, the <u>apparent magnitude</u> of a star refers to its brightness as seen from your eyes and <u>absolute magnitude</u> being the actual brightness of a star.

Read more on absolute magnitude here: brainly.com/question/1056710

#SPJ1

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A skater pushes off a wall and skates backward for a few meters before stopping.
Inessa05 [86]

Answer:

F

Explanation:

Newton's Third Law (Law of Action-Reaction) states:

Every action has an equal and opposite reaction and it occurs between two objects

In this scenario, the action would be the skater pushing off of the wall, therefore the reaction would be the wall pushing off of the skater since the two objects that are interacting are the wall and the skater.

6 0
2 years ago
A sphere of radius 0.081029 m is made of aluminum. It is submerged in flowing water with a temperature of 25 °C that results in
Dimas [21]

Answer:

its surface temperature = 54.84 ° C

Explanation:

The density of aluminium (\rho) = 2700 kg/m ³

Heat capacity ( c_p) = 897 J/Kg.K

radius of the sphere (r) = 0.081029 m

T \infty = 25 °C

T_i = 124.978  °C

time (t) = 767.276 s

Using the formula :

\frac{T-T_{ \infty} }{T_i - T_{\infty}}= e^{-\frac{hA}{\rho V c_p}}*t

where.

\frac{V}{A}= \frac{r}{3}

Replacing our values ;we have:

\frac{T-25 }{124.978 - 25}= e^{-\frac{-103.067*3}{2700*897*0.081029}}*767.276

\frac{T-25 }{124.978 - 25}= e^{{-0.001576}*767.276

\frac{T-25 }{124.978 - 25}= e^{-1.209}

\frac{T-25 }{99.978}= 0.2985

{T-25 }= 0.2985*{99.978}

{T-25 }= 29.843433

{T= 29.843433+25 }

{T= 54.843433

T ≅ 54.84 ° C

Therefore, its surface temperature = 54.84 ° C

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C electric energy would be the correct answer
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