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vitfil [10]
2 years ago
15

Perform an online search to find the structures of the compounds in the questions that follow. Provide a method for separating t

he mixtures of two or three compounds, dissolved in a solvent diethyl ether. In each case one of the components will be a neutral compound. You should give your answer in the form of a flow chart.
a) Benzophenone and tributylamine
b) 4-Bromoaniline, 3-nitrobenzoic acid, and benzoin
c) Fluorenone, octanoic acid, and dicyclohexylamine
d) 1-Hexanol and 4-bromoaniline
Chemistry
1 answer:
Vedmedyk [2.9K]2 years ago
5 0

The chemical separation method for two of the above named mixtures or compound indicated above are explained below.

<h3>What is a Chemical compound?</h3>

A chemical compound is a material generated by the chemical union of two or more elements in set quantities.

<h3>What are the separation methods?</h3>

<u>Benzophenone and tributylamine</u>

The combination of benzophenone and tributylamine is in diethyl ether (given in question). Tributylamine is a base that may readily be changed to a water soluble salt by adding an aqueous acid.

Add dilute aqueous acid to the solution. The amine salt will be present in the aqueous layer, whereas benzophenone will be present in the ether layer. A separatory funnel will isolate levels.

<u>Fluorenone, octanoic acid, and dicyclohexylamine</u>

Fluorenone, Octanoic acid, and dicyclohexyl amine: The combination comprises both an acid (octanoic acid) and a base (dicyclohexyl amine) (dicyclohexyl amine).

Add the diluted aqueous base to the solution (like NaCO3). Divide the two layers.

The acid is present in the aqueous layer as a salt, while the fluorenone and amine are present in the ether layer.

Add weak aqueous acid to this combination of fluorenone and dicyclohexyl amine.

Divide the two layers. The amine is present in the aqueous layer, and fluorenone is present in the ether.

Learn more about chemical separation at;
brainly.com/question/17143033
#SPJ1

<u></u>

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In the laboratory a student finds that it takes 44.0 Joules to increase the temperature of 10.6 grams of solid zinc from 24.9 to
BaLLatris [955]

Answer:

The specific heat of zinc is 0.361 J/g°C

Explanation:

<u>Step 1:</u> Data given

44.0 J needed

Mass of solid zinc = 10.6 grams

Initial temperature = 24.9 °C

Final temperature = 36.4 °C

<u>Step 2</u>: Calculate the specific heat of zinc

Q = m*c*ΔT

⇒ with Q = heat (in Joule) = 44.0 J

⇒ with m = the mass of the solid zinc = 10.6 grams

⇒ with c = the specific heat of the zinc = TO BE DETERMINED

⇒ with ΔT = The change in temperature = T2-T1 = 36.4 °C - 24.9 °C = 11.5 °C

44.0 J = 10.6 grams * c * 11.5°C

c = 44.0 J / (10.6g * 11.5 °C)

c = 0.361 J/g°C

The specific heat of zinc is 0.361 J/g°C

7 0
3 years ago
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
3 years ago
What type of reaction is "Separating Water"?
Lostsunrise [7]

Answer:

Decomposition

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3 years ago
Question 2: Which of the following is NOT true about streams?
mafiozo [28]

Answer:

q 3 c q 2 d

Explanation:

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A vice, you can tighten it and then work on what is held in it without having to hold it still or in the position you want. 
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