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Nataly [62]
2 years ago
6

An injector pressure drop test to see if the injector is restricted with deposits can be done using an?

Engineering
1 answer:
Vitek1552 [10]2 years ago
6 0

An injector pressure drop test to see if the injector is restricted with deposits can be done using an integer test.

<h3>What is injector strain drop?</h3>

Fuel injectors have a glide charge. This glide charge of the injector is rated at a sure strain drop throughout the injector. Meaning the injector glide is say 30#/hr at 42.five PSI. This approach that that injector will glide 30#/hr so long as the strain on the deliver side, minus the strain withinside the manifold is 42.five psiListening or Clicking Test.

Start the engine and permit it to idle. Keep the engine strolling and contact the give-up of a protracted steel screwdriver towards the gas injector. Put your ear on the alternative give up of the screwdriver. A clicking sound approaches the injector's working.

Read more about the injector pressure drop:

brainly.com/question/12385665

#SPJ1

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What are the factors of production in business? Land, labor, and capital land, capital, and interest land, labor, and customer b
kozerog [31]

Answer:

  • <em><u> Land, labor, and capital </u></em>

Explanation:

The <em>factors of production </em>are the resources that are used to produce goods and services.

By definition resources are scarce.

<em>Land</em> includes everything that comes from the land, that can be used as raw material to produce other materials; for instance, water, minerals, wood.

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<em>Capital</em> is the facilites (buildings), machinery, equipments, tools that the persons use to produce goods or services. For instance, a computer, a chemical reactor, or a pencil.

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6 0
4 years ago
Read 2 more answers
Ammonia contained in a piston-cylinder assembly, initially saturated vapor at 0o F, undergoes an isothermal process during which
Rudik [331]

ANSWERS:

-P_{2(a)} =15.6lbf/in^2\\-P_{2(b)} =30.146lbf/in^2\\ T_{2(a)} =0^oF\\T_{2(b)} =0^oF\\x_{2(b)} =49.87percent

Explanation:

Given:

Piston cylinder assembly which mean that the process is constant pressure process P=C.

<u>AMMONIA </u>

state(1)

saturated vapor x_{1} =1

The temperature T_{1} =0^0 F

Isothermal process  T=C

a)

-V_{2} =2V_{1} ( double)

b)

-V_{2} =.5V_{2} (reduced by half)

To find the final state by giving the quality in lbf/in we assume the friction is neglected and the system is in equilibrium.

state(1)

using PVT data for saturated ammonia

-P_{1} =30.416 lbf/in^2\\-v_{1} =v_{g} =9.11ft^3/lb

then the state exists in the supper heated region.

a) from standard data

-v_{1(a)} =2v_{1} =18.22ft^3/lb\\-T_{1} =0^oF

at\\P_{x} =14lbf/in^2\\-v_{x} =20.289 ft^3/kg

at\\P_{y} =16 lbf/in^2\\-v_{y} =17.701ft^3/kg

assume linear interpolation

\frac{P_{x}-P_{2(b)}  }{P_{x}- P_{y} } =\frac{v_{x}-v_{1(a)}  }{v_{x}-v_{y}  }

P_{1(b)}=P_{x} -(P_{x} -P_{y} )*\frac{v_{x}- v_{1(b)} }{v_{x}-v_{y}  }\\ \\P_{1(b)} =14-(14-16)*\frac{20.289-18.22}{20.289-17.701} =15.6lbf/in^2

b)

-v_{2(a)} =2v_{1} =4.555ft^3/lb\\v_{g}

from standard data

-v_{f} =0.02419ft^3/kg\\-v_{g} =9.11ft^3/kg\\v_{f}

then the state exist in the wet zone

-P_{s} =30.146lbf/in^2\\v_{2(a)} =v_{f} +x(v_{g} -v_{f} )

x=\frac{v_{2(a)-v_{f} } }{v_{g} -v_{f} } \\x=\frac{4.555-0.02419}{9.11-0.02419} =49.87%

3 0
3 years ago
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