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3 years ago

The branding, packaging, and labeling of your product should accomplish all of the following except

Engineering

1 answer:

Radda [10]3 years ago

7 0

Answer:what is the following

Explanation:

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Sedimentary rock forms at or near the

Natalija [7]

I believe it’s A bit I. could be wrong

5 0

3 years ago

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A tee requires three studs and three cripples.<br> O TRUE<br> O FALSE

NARA [144]

Answer:

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3 0

3 years ago

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A piston-cylinder assembly contains 2 lb of air at a temperature of 540 degrees R and a pressure of 1 atm. The air is compressed

attashe74 [19]

Answer:

$W=-123.8Btu$

Explanation:

Hello,

In this problem, the piston-cylinder assembly make us state the energy balance as:

$Q-W=\Delta U$

Thus, we must now compute $\Delta U$ in terms of Cv as follows:

$\Delta U=mCv(T_2-T_1)\\\Delta U=2lb*0.173\frac{Btu}{lb*R}*(840R-540R)\\ \Delta U=103.8Btu$

Now, since heat is given off, its sign is negative, thus, the work is computed as:

$W=Q-\Delta U\\W=-20Btu-103.8Btu=-123.8Btu$

This work means that work was done over the system in order to allow the compression.

The suppositions were:

- The change in the internal energy is a function of the temperature.

- Air is an ideal gas.

Best regards.

8 0

4 years ago

E total kinetic energy of a 2500 lbm car when it is moving at 80 mph (in BTU)?

Galina-37 [17]

Answer:

KE= 687.21 BTU

Explanation:

Given that

Mass of car = 2500 lbm

We know that 1 lb=0.45 kg

So the mass of car m =1133.98 kg

Velocity of car= 80 mph

We know that 1 mph =0.44 m/s

So velocity of car = 35.76 m/s

As we know that kinetic energy (KE) is given as follows

$KE=\dfrac{1}{2}mv^2$

Now by putting the values

$KE=\dfrac{1}{2}\times 1133.98\times 35.76^2$

KE=725.05 KJ

We know that 1 KJ = 0.94 BTU

So KE= 687.21 BTU

3 0

4 years ago

A single lane highway has a horizontal curve. The curve has a super elevation of 4% and a design speed of 45 mph. The PC station

andreyandreev [35.5K]

Answer: 112 + 19.27

Explanation:

Super elevation is an inward transverse slope provided through out the length of the horizontal curve which ends up serving as a counteract to the centrifugal force and checks tendency of overturning. It changes from infinite radius to radius of a transition curve.

Super curve elevation (e) = 4%

4/100= 0.04

e= V^2/gR

Make R the subject of the formula.

egR= V^2

R= V^2/eg

V= 45mph

=45 × 0.44704m/s

=20.1168m/s

g (force due to gravity) =9.81

Therefore,

R= (20.1168)^2/9.81 × 0.04

= 1031.31m

Tangent Length( T) = PI - PC

Tangent Length= 10875 - 10500

=375m

T= R Tan(I/2)

375= 1031.31 × Tan(I/2)

I= 39.96

Also,

L= πRI/180

= 719.27m

Station PT= Stat PC+ L

10500 + 719.27

=11219.27

=112 + 19.27

6 0

3 years ago