Answer:
375.2 kJ
Explanation:
- H₂(g) +F₂(g) → 2HF(g) +536kJ
The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.
We can then <u>state a rule of three</u>:
And <u>solve for X</u>:
- X = 1.4 mol * 536 kJ / 2 mol
28 degrees below freezing would be 4 degrees
Answer:
The answer to your question is V2 = 333.9 ml
Explanation:
Data
Pressure 1 = P1 = 1.977 atm
Volume 1 = V1 = 517.4 ml
Pressure 2 = P2 = 3.063 atm
Volume 2 = V2 = ?
Process
To solve this problem use Boyle's law
P1V1 = P2V2
-Solve for V2
V2 = P1V1/P2
-Substitution
V2 = (1.977 x 517.4) / 3.063
-Simplification
V2 = 1022.9 / 3.063
-Result
V2 = 333.9 ml
