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irinina [24]
2 years ago
14

6.A truck is carrying a steel beam of length 13.0 m on a freeway. An accident causes the beam to be dumped off the truck and sli

de horizontally along the ground at a speed of 30.0 m/s. The velocity of the center of mass of the beam is northward while the length of the beam maintains an east–west orientation. The vertical component of the Earth's magnetic field at this location has a magnitude of 30.0 T. What is the magnitude of the induced emf between the ends of the beam?
Physics
2 answers:
nataly862011 [7]2 years ago
7 0
11234533534534334634354
labwork [276]2 years ago
3 0

The magnitude is 13.12 mV.

The steps are attached below.

<h3>How do you find the magnitude of an induced emf?</h3>

The standard SI unit of the magnetic field is the tesla (T). As an end result, we can use these equations and the equation for an induced emf due to changes in magnetic flux, ϵ=−NΔϕΔt ϵ = − N Δ ϕ Δ t, to calculate the importance of a precipitated emf in a solenoid.

The magnitude of the precipitated contemporary depends on the rate of trade of magnetic flux or the fee of reducing the magnetic area strains.

Learn more about the magnitude here: brainly.com/question/18109453

#SPJ2

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Firdavs [7]

Initial velocity (u) = 2 m/s

Acceleration (a) = 10 m/s^2

Time taken (t) = 4 s

Let the final velocity be v.

By using the equation,

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3 years ago
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A beam of electrons passes through a single slit, and a beam of protons passes through a second, but identical, slit. The electr
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Answer:

(b) The electrons, because they have the smaller momentum and, hence, the larger de Broglie wavelength

Explanation:

de Broglie wavelength λ = h / m v

Since both electrons and protons have same velocity , momentum mv will be less for electrons because mass of electron is less .

for electron , momentum is less so  . Therefore de Broglie wavelength λ will be more for electrons .

Amount of diffraction that is angle of diffraction is proportional to λ

Therefore electrons having greater de Broglie wavelength will show greater diffraction.

7 0
3 years ago
A particle with positive charge q = 9.61 10-19 C moves with a velocity v = (5î + 4ĵ − k) m/s through a region where both a unifo
user100 [1]

Answer:

\vec{F}=(1.537*10^{-17}\hat{i}-9.61*10^{-19}\hat{j}-2.883*10^{-18}\hat{k})N

Explanation:

The total force on the particle is given by

\vec{F}=q\vec{v}\ X\ \vec{B}+q\vec{E}

Then, by replacing we have:

q\vec{v}\ X \vec{B}=q[7\hat{k}-9\hat{j}-\hat{k}]\\\\q\vec{E}=q[5\hat{i}-\hat{j}-2\hat{k}]\\\\\vec{F}=(9.61*10^{-19}C)[(7+9)\hat{i}+(-9-1)\hat{j}+(-1-2)\hat{k}]\\\\\vec{F}=(1.537*10^{-17}\hat{i}-9.61*10^{-19}\hat{j}-2.883*10^{-18}\hat{k})N

where the cross product can be made with the determinant method.

Hope this helps!!

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4 years ago
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A baseball with a mass of 151 g is thrown horizontally with a speed of 39.5 m/s (88 mi/h) at a bat. The ball is in contact with
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Answer:

the average force exerted on the ball by the bat is 11,613.27 N

Explanation:

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mass of the baseball, m = 151 g = 0.151 kg

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final velocity of the baseball, v = 45.1 m/s

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The average force exerted on the ball by the bat is calculate as;

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Therefore, the average force exerted on the ball by the bat is 11,613.27 N

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3 years ago
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