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3 years ago

A ball is thrown straight upward and rises to a maximum

Physics

1 answer:

Leviafan [203]3 years ago

3 0

Answer:

Explanation:

As we know that the ball is projected upwards so that it will reach to maximum height of 16 m

so we have

$v_f^2 - v_i^2 = 2 a d$

here we know that

$v_f = 0$

also we have

$a = -9.81 m/s^2$

so we have

$0 - v_i^2 = 2(-9.81)(16)$

$v_i = 17.72 m/s$

Now we need to find the height where its speed becomes half of initial value

so we have

$v_f = 0.5 v_i$

now we have

$v_f^2 - v_i^2 = 2 a d$

$(0.5v_i)^2 - v_i^2 = 2(-9.81)h$

$-0.75v_i^2 = -19.62 h$

$0.75(17.72)^2 = 19.62 h$

$h = 12 m$

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A long, straight wire of radius R carries a steady current I that is uniformly distributed through the cross section of the wire

vitfil [10]

Answer:

When $r \ge R$

$B = \frac{ \mu_o * I}{ 2 \pi r }$

When $r< R$

$B = [\frac{\mu_o * I }{ 2 \pi R^2} ]* r$

Explanation:

From the question we are told that

The radius is R

The current is I

The distance from the center

Ampere's law is mathematically represented as

$B[2 \pi r] = \mu_o * \frac{I r^2 }{R^2 }$

$B = \frac{ \mu_o}{2 \pi } * \frac{r}{R^2}$

When $r \ge R$

=> $B = \frac{ \mu_o * I}{ 2 \pi r }$

But when $r< R$

$B = [\frac{\mu_o * I }{ 2 \pi R^2} ]* r$

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4 years ago

A student wants to use a ramp to move boxes into a truck bed that is 3 m high. He has a choice of 2 different ramps. The length

Morgarella [4.7K]

Answer:

The correct option is;

B. 8 m, because he has to apply less force over a greater distance

Explanation:

In the given question, in order for the student to lift the boxes onto the tuck with less amount of force, he applies the principle of Mechanical Advantage

The mechanical advantage is given by the measure by which a force is amplified through the use of a tool

Given that the work done = The force × The distance, we have

F₁ × d₁ = F₂ × d₂, which gives;

d₁/d₂ = F₂/F₁

Where;

F₁ = The input force

F₂ = The output force

d₁ = The input distance

d₂ = The output distance

The Mechanical advantage, MA = d₁/d₂ = F₂/F₁

Therefore, when the input distance is increased the input force will be reduced for a given output force

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3 years ago

An object in a fluid experiences a buoyant force from the fluid. If the object is completely immersed, on which does the magnitu

loris [4]

Answer:

Weight of the fluid that the object displaces.

Explanation:

When the fluid is completely immersed in a fluid, it experiences pressure from all the direction. While the object is immersed in the fluid a force acts on it in the opposite direction, i.e., upwards. This force is termed as buoyant force.

Also, as per the Archimedes' Principle, the force experience by the object is the same as the weight of the fluid that gets displaced by the object.

Thus on complete immersion of the object in the fluid, it experiences the force same as the weight of the fluid that gets displaced

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3 years ago

The resistivity of gold is 2.44 x 10-8 ohms.m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries

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Answer:

E=0.036 V/m

Explanation:

Given that

Resistivity ,ρ=2.44 x 10⁻⁸ ohms.m

d= 0.9 mm

L= 14 cm

I = 940 m A = 0.94 A

We know that electric field E

E= V/L

V= I R

R=ρL/A

So we can say that

E= ρI/A

Now by putting the values

$E=\dfrac{ 2.44\times 10^{-8}\times 0.94}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}$

E=0.036 V/m

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3 years ago

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3 years ago