I don’t think I know that
Answer:
The dynamic viscosity and kinematic viscosity are 
lb-s/in2 and 
in2/s.
Explanation:
Step1
Given:
Inner diameter is 2.00 in.
Gap between cups is 0.2 in.
Length of the cylinder is 2.5 in.
Rotation of cylinder is 10 rev/min.
Torque is 0.00011 in-lbf.
Density of the fluid is 850 kg/m3 or 0.00095444 slog/in³.
Step2
Calculation:
Tangential force is calculated as follows:
T= Fr
F = 0.00011 lb.
Step3
Tangential velocity is calculated as follows:
V=1.0472 in/s.
Step4
Apply Newton’s law of viscosity for dynamic viscosity as follows:
lb-s/in².
Step5
Kinematic viscosity is calculated as follows:
in2/s.
Thus, the dynamic viscosity and kinematic viscosity are lb-s/in2 and in2/s.
Answer:
c) absolute zero
Explanation:
The fourth principle of thermodynamics posed by the Romanian economist Nicholas Georgescu-Roegen, explains the presence of absolute zero is said that at this temperature the internal molecular movement becomes zero making the internal energy (U) zero, absolute zero is equivalent to -273.15C or 0Kelvin
Answer:
Between 35°– 45°
Explanation:
In the vertical position, Point the flame in the direction of travel. Keep the flame tip at the correct height above the base metal. An angle of 35°–45° should be maintained between the torch tip and the base metal. This angle may be varied up or down to heat or cool the weld pool if it is too narrow or too wide
