Given:
The distance between the two narrow slits is
The distance between the slit and the screen is
The wavelength of the light is
Required: Distance of the third bright fringe from the central maximum.
Explanation:
The third bright fringe will have m = 3.
The distance of the third bright fringe from the central maximum can be calculated by the formula
On substituting the values, the distance can be calculated as
Final Answer: The distance of the third bright fringe from the central maximum is 0.0179 m.
Acceleration represents the change in velocity.
Answer:
B
Explanation:
The iris controls the amount of light that enters the eye by opening and closing the pupil. The iris uses muscles to change the size of the pupil. These muscles can control the amount of light entering the eye by making the pupil larger (dilated) or smaller (constricted).
Answer:
Range will become 4 times of initial range
Explanation:
Let the velocity of projection is u
And angle at which projectile is projected is 
And acceleration due to gravity is 
So range of projectile is equal to 
........eqn 1
Now in second case it is given that velocity of launching is doubled
So new velocity 
So new range will be equal to 
.....eqn 2
Now dividing eqn 2 by eqn 1
So if we double the initial launch speed then range will become 4 times
False. Heat radiation from the sun cannot reach Earth, we cannot receive TV or GPS signals from satellites, and we cannot detect the light from distant stars.
Oh, wait . . .
