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storchak [24]
2 years ago
8

Lab: Energy Transfer Instructions Click the links to open the resources below. These resources will help you complete the assign

ment. Once you have created your file(s) and are ready to upload your assignment, click the Add Files button below and select each file from your desktop or network folder. Upload each file separately. Your work will not be submitted to your teacher until you click Submit. Documents Descriptive Lab Report Guide Descriptive Lab Report Rubric
Physics
2 answers:
jonny [76]2 years ago
8 0

Answer:

The second one says cant open file............

svetoff [14.1K]2 years ago
6 0

Answer:

Give me a 5 star

Explanation:

Because im cool

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Which of the waves has the smallest amplitude?
balandron [24]

Answer:

I think its the Blue wave, im not sure so dont take my word for it.

Explanation:

3 0
2 years ago
A ___ is the unit of measurement for force.
bogdanovich [222]

Answer:

Newton (N)

Explanation:

A newton is the unit of measurement for force

4 0
3 years ago
The plug has a diameter of 30 mm and fits within a rigid sleeve having an inner diameter of 32 mm. Both the plug and the sleeve
Katena32 [7]

Answer:

P=740 KPa

Δ=7.4 mm

Explanation:

Given that

Diameter of plunger,d=30 mm

Diameter of sleeve ,D=32 mm

Length .L=50 mm

E= 5 MPa

n=0.45

As we know that

Lateral strain

\varepsilon _t=\dfrac{D-d}{d}

\varepsilon _t=\dfrac{32-30}{30}

\varepsilon _t=0.0667

We know that

n=-\dfrac{\epsilon _t}{\varepsilon _{long}}

\varepsilon _{long}=-\dfrac{\epsilon _t}{n}

\varepsilon _{long}=-\dfrac{0.0667}{0.45}

\varepsilon _{long}=-0.148

So the axial pressure

P=E\times \varepsilon _{long}

P=5\times 0.148

P=740 KPa

The movement in the sleeve

\Delta =\varepsilon _{long}\times L

\Delta =0.148\times 50

Δ=7.4 mm

6 0
3 years ago
Which group of people was most directly affected by the twenty sixth amendment
vladimir2022 [97]
Adults. 18years olds and older were affected because back then only 21 years olds and older could vote but the 26th amendment changed that
4 0
3 years ago
Read 2 more answers
Part A Determine the magnitude of the x component of F using scalar notation. Fx F x = nothing lb Request Answer Part B Determin
maksim [4K]

As we know that force F makes an angle of 60 degree with X axis

so the X component is given as

cos60 = \frac{F_x}{F}

now we have

F_x = F cos60

F_x = 0.50 F

Similarly we know that force F makes an angle of 45 degree with Y axis

so the X component is given as

cos45 = \frac{F_y}{F}

now we have

F_y = F cos45

F_y = 0.707 F

Now for the component along z axis we know that

F_x^2 + F_y^2 + F_z^2 = F^2

now plug in all components

(0.707 F)^2 + (0.50 F)^2 + F_z^2 = F^2

0.5 F^2 + 0.25 F^2 + F_z^2 = F^2

F_z^2 = F^2(1 - 0.75)

F_z^2 = 0.25 F^2

F_z = 0.5 F

5 0
3 years ago
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