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Helga [31]
3 years ago
12

The following electrical characteristics have been determined for both intrinsic and p-type extrinsic gallium antimonide (GaSb)

at room temperature: σ (????∙m) –1 n (m–3 ) p (m–3 ) Intrinsic 8.9 × 10^4 8.7 × 10^23 8.7 × 10^23Extrinsic 2.3 × 10^5 7.6 × 10^22 1.0 × 10^25 (p-type)Calculate electron and hole mobilities.

Engineering
1 answer:
xxTIMURxx [149]3 years ago
6 0

Answer:

0.5m^2/Vs and 0.14m^2/Vs

Explanation:

To calculate the mobility of electron and mobility of hole for gallium antimonide we have,

\sigma = n|e|\mu_e+p|e|\mu_h (S)

Where

e= charge of electron

n= number of electrons

p= number of holes

\mu_e= mobility of electron

\mu_h=mobility of holes

\sigma = electrical conductivity

Making the substitution in (S)

Mobility of electron

8.9*10^4=(8.7*10^{23}*(-1.602*10^{-19})*\mu_e)+(8.7*10^{23}*(-1.602*10^{-19})*\mu_h)

0.639=\mu_e+\mu_h

Mobility of hole in (S)

2.3*10^5 = (7.6*10^{22}*(-1.602*10^{-19})*\mu_e)+(1*10^{25}*(-1.602*10^{-19}*\mu_h))

0.1436 = 7.6*10^{-3}\mu_e+\mu_h

Then, solving the equation:

0.639=\mu_e+\mu_h (1)

0.1436 = 7.6*10^{-3}\mu_e+\mu_h (2)

We have,

Mobility of electron \mu_e = 0.5m^2/V.s

Mobility of hole is \mu_h = 0.14m^2/V.s

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Answer:

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\Delta t_{mean} = \frac{1 + \sqrt{2} }{6000}\,h

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