Answer:
The answer is 380.32×10^-6
Refer below for the explanation.
Explanation:
Refer to the picture for brief explanation.
Answer:
Math and Computer Skills. A qualified engineer should be good at math, at least through the level of calculus and trigonometry, and understand the importance of following the data when making design decisions.
Organization and Attention to Detail.
Curiosity.
Creativity.
Critical Thinking.
Intuition.
Explanation:
R = distance
dr/dt speed or with a direction, velocity
d(dr/dt)/dt = the time derivative of the velocity is called acceleration.
Speed is a scalar. Acceleration is a vector.
Answer: the answer is plagiarism.
Explanation: Plagiarism is the act of taking credit from someone else's works or ideas, without acknowledging the author. <u>Conflict of interest</u> occurs when an employee has <u>interests that are at odds to each other</u>, which isn't shown at the excerpt given in the exercise. <u>Fabrication</u> is the <u>creation of intellectual property</u>, also not shown in the exercise, and <u>falsification</u> is the <u>creation of a scientific hypothesis</u> that <u>cannot be verified</u> by lack of practical evidence, which is not the case described as well.
Answer:
8861.75 m approximately 8862 m
Explanation:
We need to remember Newton's 2nd Law which says that the force experienced by an object is proportional to his acceleration and that the constant of proportionality between those two vectors correspond to the mass of the object.
for the weight of an object (which is a force) we have that the acceleration experienced by that object is equal to the gravitational acceleration, obtaining that 
For simplicity we work with
despiting the effect of the height above sea level. In this problem, we've been asked by the height above sea level that makes the weight of an object 0.30% more lighter.
In accord with the formula
the "normal" or "standard" weight of an object is given by
when
, so we need to find the value of
that makes
meaning that the original weight decrease by a 0.30%, so now we operate...
now we group like terms on the same sides
we cancel equal tems on both sides and obtain that 