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Shtirlitz [24]
3 years ago
14

Infinitivo de vivia kkk xd

Engineering
1 answer:
blagie [28]3 years ago
8 0

Answer:

pls put a question not random letters

Explanation:

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A lake is fed by a polluted stream and a sewage outfall. The stream and sewage wastes have a decay rate coefficient (k) of 0.5/d
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Given :

k = 0.5 per day

$C_s = 10 \ mg/L \ ; \ \ Q_s= 40 \ m^3/s$

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Volume, V $= 200 \ m^3$

Now, input rate = output rate + KCV ------------- (1)

Input rate  $= Q_s C_s + Q_{sw}C_{sw}$

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                $= 2 \times 10^5 \ mg/s$

The output rate $= Q_m C_{m}$

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                          $=40.5 \times 10^3 \ C \ mg/s$

Decay rate = KCV

∴$KCV =\frac{0.5/d \times C \  \times 200 \times 1000}{24 \times 3600}$

            = 1.16 C mg/s

Substituting all values in (1)

$2 \times 10^5 = 40.5 \times 10^3 \ C+ 1.16 C$

C = 4.93 mg/L

4 0
3 years ago
A CUSTOMER BRINGS HER CAR INTO THE
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