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Sedbober [7]
4 years ago
8

Calculate the ph of an aqueous solution that is 0.045 m in hcl(aq) at 25°c

Chemistry
1 answer:
ivann1987 [24]4 years ago
4 0
Remember that HCl is a strong acid will dissociate almost 100%
HCl + H₂O --> H₃O⁺ + Cl⁻

pH = -log[H₃O⁺]
pH = -log(0.045) = 1.35

(The rules for sig figs are that if you take the log of a number with x significant figures, then the result should have x significant decimal places.)

The pH is 1.35
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