Relative velocity.....Please help....
1 answer:
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Answer:
Hope the above picture might help you :)
Answer:
= 0.331 J / g ° C
Explanation:
We have a calorimetry exercise where all the heat yielded by one of the components is absorbed by the other.
Heat ceded Qh = m1 ce1 ( -
)
Heat absorbed Qc = m2 ce2 ( - T₀)
Body 1 is metal and body 2 is water . Where m are the masses of the two bodies, ce their specific heat and T the temperatures
Qh = Qc
m₁ (
-
) = m₂
(
- T₀)
we clear the specific heat of the metal
= m₂
(
- T₀) / (m₁ (
-
))
= 50.00 4.184 (20.15 -10.79) / (75.00 (99.0-20.15))
= 209.2 (9.36) / (75 78.85)
= 1958.11 / 5913.75
= 0.331 J / g ° C
Answer:
200 nm.
Explanation:
The minimum thickness can be found using the following equation:
Where:
t: is the thickness =?
m: is the order of interference = 1 (since it is minimum)
n: is the refractive index = 1.25
λ: is the wavelength = 500 nm
Therefore, the minimum thickness is 200 nm.
I hope it helps you!