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Kisachek [45]
2 years ago
14

The density of water is 1 g/cm3. brent used the following method to convert 1 g/cm3 to kg/m3.

Chemistry
1 answer:
11111nata11111 [884]2 years ago
7 0

Answer:

a) The wrong denominator for the equivalent fraction of kilograms to grams

b) The use of the scale factor of length rather than the scale factor of volume for the equivalent fraction of cubic centimeters to cubic meters

c) The arrival at the correct 1000 kg/m³ rather than 0.1 g/m³ based on the expression on the left of the equation

The density of water = 1 g/cm³

The given equation is presented as follows;

1 g/cm³ × 1 kg/(1000 kg) × 100 cm³/(1 m³) = 1000 kg/m³

The error in the conversion method are;

a) The conversion, 1 kg/(1,000 kg) has an error, the correct conversion is (1 kg)/1,000 g)

b) The volume conversion error, 100 cm³/(1 m³), the correct volume conversion is (100 cm)³/(1 m³) = 1,000,000 cm³/(1 m³)

c) The right of the equal to sign error; using the left side expression only, the (wrong) answer is 0.1 g/m³

The correct equation is presented as follows;

1 g/cm³ × 1 kg/(1000 g) × 1,000,000 cm³/(1 m³) = 1000 kg/m³

Explanation: hope this help.

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Explanation:

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What is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 193.9J of heat and the temperature rises 15.0
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Answer:

The specific heat capacity of silver is 0.24 j/g.°C.

Explanation:

Given data:

Mass of sample = 55.00 g

increase of temperature ΔT= 15.0 °C

Heat absorbed = 193.9 J

Specific heat capacity of silver = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance.

ΔT = change in temperature

Now we will put the values in formula.

193.9 J = 55.00 g × c ×15.0 °C

193.9 J = 825 g.°C  × c

c = 193.9 J / 825  g.°C

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The specific heat capacity of silver is 0.24 j/g.°C.

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