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german
2 years ago
14

Why are the two equilibrium reactions below not affected by an increase in pressure?

Chemistry
1 answer:
dexar [7]2 years ago
4 0

An increase in pressure does not affect the reaction because the moles of reactants and products or the pressure of the forward reaction are equal at equilibrium.

<h3>What is chemical equilibrium?</h3>

A chemical reaction is in equilibrium if the rate of the backward reaction and the forward reaction are equal.

Pressure affects the equilibrium position of chemical reactions involving gases.

For the given reactions in equilibrium, moles of reactants and products and hence, the pressure of the forward reaction are equal at equilibrium, therefore, an increase in pressure does not affect it.

Therefore, an increase in pressure will only affect the equilibrium of a reaction in which the pressure varies in the forward and backward reaction.

Learn more about pressure and equilibrium at: brainly.com/question/14424255

#SPJ1

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Should be 1.8L.
2 moles of hydrogen react with 1 mole of oxygen. If 2 moles of hydrogen is 3.6L, 1 mole of oxygen should be 1.8L.
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3 years ago
A chemist takes 50-gram sample of sulfur powder that has a melting point of 115.2 °C. What is the melting point of a 100-gram sa
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Answer:

115.2 °C since melting point is an intensive property  

Step-by-step explanation:

The melting point of a substance does not depend on how much you have.

For example, the melting point of water is 0 °C, whether it is an ice cube from the refrigerator or in the frozen pond outside.

The freezing point of a substance is an <em>intensive property</em>.

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3 years ago
Is CH3NH2O ionic or covalent
Ivahew [28]

Answer:

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Explanation:

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3 years ago
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What mass of solute should you measure out in order to make 1,000 mL of a 0.3 M solution of magnesium phosphate Mg3(PO4)2?
vivado [14]

Hey there !

Molecular Weight: 262.86 g/mol

Volume in liters : 1,000 mL => 1,000 / 1000 => 1 L

Number of moles of solution :

number of moles = volume x molarity

number of moles = 1 x 0.3  => 0.3 moles

Therefore:

1 mole Mg₃(PO₄)₂ ------------------- 262.86 g

0.3 moles ----------------------------- mass of Mg₃(PO₄)₂  ??

mass of Mg₃(PO₄)₂ = 0.3 x 262.86 / 1

mass of Mg(PO₄)₂ => 78.858 g

Hope this helps!

7 0
3 years ago
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