2. The new pressure, given the data is 3.0 atm
3. The new temperature in K is 361 K
4. The new temperature in K is 348 K
<h3>2. How to determine the new pressure</h3>
- Initial volume (V₁) = 1500 mL
- Initial pressure (P₁) = 3.4 atm
- Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
- New temperature (T₂) = 75 °C = 75 + 273 = 348 K
- New Volume (V₂) = 2000 mL
- New pressure (P₂) = ?
The new pressure of the gas can be obtained by using the combined gas equation as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
(3.4 × 1500) / 298 = (P₂ × 2000) / 348
Cross multiply
P₂ × 2000 × 298 = 3.4 × 1500 × 348
Divide both sides by 2000 × 298
P₂ = (3.4 × 1500 × 348) / (2000 × 298)
P₂ = 3.0 atm
<h3>3. How to determine the new temperature</h3>
- Initial volume (V₁) = 450 mL
- Initial pressure (P₁) = 167 KPa
- Initial temperature (T₁) = 295 K
- New pressure (P₂) = 230 KPa
- New Volume (V₂) = 400 mL
- New temperature (T₂) =?
The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
(167 × 450) / 295 = (230 × 400) / T₂
Cross multiply
T₂ × 167 × 450 = 295 × 230 × 400
Divide both sides by 167 × 450
T₂ = (295 × 230 × 400) / (167 × 450)
T₂ = 361 K
<h3>4. How to determine the new temperature</h3>
- Initial volume (V₁) = 3.6 L
- Initial pressure (P₁) = 9.2 atm
- Initial temperature (T₁) = 298 K
- New Volume (V₂) = 5.3 L
- New pressure (P₂) = 7.3 atm
- New temperature (T₂) =?
The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
(9.2 × 3.6) / 298 = (7.3 × 5.3) / T₂
Cross multiply
T₂ × 9.2 × 3.6 = 298 × 7.3 × 5.3
Divide both sides by 9.2 × 3.6
T₂ = (298 × 7.3 × 5.3) / (9.2 × 3.6)
T₂ = 348 K
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