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2 years ago

What is the bonding requirement for carbon atoms?

Chemistry

1 answer:

Artyom0805 [142]2 years ago

7 0

Answer:

carbon atoms tend to make four bonds, each carbon atom will have the number of hydrogen atoms that are required for four bonds. This compound contains 16 hydrogen atoms for a molecular formula of C 8 H 16.

Explanation:

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You add 7.8 g of iron to 20.70 mL of water and observe that the volume of iron and water together is 21.69 mL . Calculate the de

bixtya [17]

21.69mL - 20.70mL = .99mL Fe
7.8 g / .99 mL = 7.9g/mL

4 0

3 years ago

Ammonia and oxygen react to form nitrogen monoxide and water. Construct your own balanced equation to determine the amount of NO

stiv31 [10]

Answer:

NO would form 65.7 g.

H₂O would form 59.13 g.

Explanation:

Given data:

Moles of NH₃ = 2.19

Moles of O₂ = 4.93

Mass of NO produced = ?

Mass of produced H₂O = ?

Solution:

First of all we will write the balance chemical equation,

4NH₃ + 5O₂ → 4NO + 6H₂O

Now we will compare the moles of NO and H₂O with ammonia from balanced chemical equation:

NH₃ : NO NH₃ : H₂O

4 : 4 4 : 6

2.19 : 2.19 2.19 : 6/4 × 2.19 = 3.285 mol

Now we will compare the moles of NO and H₂O with oxygen from balanced chemical equation:

O₂ : NO O₂ : H₂O

5 : 4 5 : 6

4.93 : 4/5×4.93 = 3.944 mol 4.93 : 6/5 × 4.93 = 5.916 mol

we can see that moles of water and nitrogen monoxide produced from the ammonia are less, so ammonia will be limiting reactant and will limit the product yield.

Mass of water = number of moles × molar mass

Mass of water = 3.285 mol × 18 g/mol

Mass of water = 59.13 g

Mass of nitrogen monoxide = number of moles × molar mass

Mass of nitrogen monoxide = 2.19 mol × 30 g/mol

Mass of nitrogen monoxide = 65.7 g

4 0

3 years ago

To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?

poizon [28]

We know that to relate solutions of with the factors of molarity and volume, we can use the equation: $M_{1} V_{1} = M_{2} V_{2}$

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M $H_{2} SO_{4}$ is the left side of the equation. Then we have:

$(18 M)(0.050 L)=(4.35M) V_{2}$

We can then solve for $V_{2}$ :

$V_{2}= \frac{(18M)(0.05L)}{4.35M}$ and $V_{2} =0.21 L$ or $210 mL$

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.

7 0

3 years ago

If a material mixes readily with water it is identified as

Rama09 [41]

If a material mixes readily with water it is describe as HYDROPHILIC. Hydrophilic substances are water loving molecules, there reaction with water is favorable in term of thermodynamics. This type of substance are usually charged and often have ability to get involve in hydrogen bonding.

3 0

3 years ago

2. What effect does adding a neutron have on the atom’s mass?

anyanavicka [17]

It does, however, change the mass of the nucleus. Adding or removing neutronsfrom the nucleus are how isotopes are created. Protons carry a positive electrical charge and they alone determine the charge of the nucleus.

7 0

3 years ago