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Verdich [7]
2 years ago
13

What is the bonding requirement for carbon atoms?

Chemistry
1 answer:
Artyom0805 [142]2 years ago
7 0

Answer:

carbon atoms tend to make four bonds, each carbon atom will have the number of hydrogen atoms that are required for four bonds. This compound contains 16 hydrogen atoms for a molecular formula of C 8 H 16.

Explanation:

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Draw the structure for cis-2,3-dibromo-2-hexene.
padilas [110]
First, draw the 2-hexene. Th is is a molecule of six carbons with a double bond in the second carbon:

      CH3 - CH = CH2 - CH2 - CH2 - CH3

Secong, put one Br on the second carbon and one Br on the third carbon:

    CH3 - CBr = CBr - CH2 - CH2 - CH3

Third, cis means that the two Br are placed in opposed positions, this is drawn with one Br up and the other down. So, you need to represent the position of the Br in the space:


      H   Br          H     H      H
       |    |             |       |       |
H - C - C = C -  C  -  C  -  C - H
       |           |      |       |       |
      H          Br   H     H      H

The important fact to realize is that the two Br are in opposed sides of the molecule.
4 0
3 years ago
Read 2 more answers
How many moles are in 110 grams of nahco3
yuradex [85]
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1 mole ---------- 84 g
? mole ---------- 110 g

moles NaHCO₃ = 110 . 1 / 84

moles NaHCO₃ = 110 / 84

= 1.309 moles

hope this helps!
4 0
3 years ago
The lowest possible concentration of free hydrogen ions is represented by a ph value of
spayn [35]
PH is the logarithmic measure of the concentration of hydrogen ions in solution. In an aqueous system, the lowest possible concentration of H+ ions (least acidic) is 1x 10^-14. The -log(1x10^-14) = pH of 14
6 0
3 years ago
In the diagram below, west is to the left, east is to the right, and the observer is looking toward the north. What is the direc
Damm [24]
I think the answer is c since the it’s looking at NW, the wind is coming from SE
7 0
2 years ago
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What is the mass of calcium in 2.3•10^23 molecules of calcium phosphate
Katena32 [7]

Explanation:

N(Ca)=3×N(Ca₃(PO₄)₂)=

=3×2.3×10²³=6.9×10²³

6.02×10²³→40g

6.9×10²³→Xg

m(Ca)=X≈45.85g

3 0
3 years ago
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