Question

Three professional wrestlers are fighting over a champion’s belt, and each exerts a force on the belt. Wrestler 1 exerts a force F1=40.0 N in the +x-direction, wrestler 2 exerts a force F2=80.0 N in the negative y-direction, and wrestler 3 exerts a force F3=60.0 N at an angle of 36.9° counterclockwise (anticlockwise) from the +x-direction.

Answer 1

The resultant force of the three professional wrestlers on the championship belt is 98.35 N.

Component of the forces in x - direction

The component of the forces in x -direction is calculated as follows;

Fx = 40 N  +  60(cos 36.9)

Fx = 40 N + 47.98 N

Fx = 87.98 N

Component of the forces in y - direction

The component of the forces in y -direction is calculated as follows;

Fy = -80 N + 60(sin 36.9)

Fy = -43.95 N

Resultant force

R = √Fx² + Fy²

R = √( 87.98²  + 43.95²)

R = 98.35 N

Thus, the resultant force of the three professional wrestlers on the championship belt is 98.35 N.

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