Answer:
(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East
(b) When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West
Explanation:
Given;
a force vector points due east,
= 140 N
let the second force = ![F_2](https://tex.z-dn.net/?f=F_2)
let the resultant of the two vectors = F
(a) When the resultant force is pointing along east line
the second force must be pointing due east
![F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N](https://tex.z-dn.net/?f=F%20%3D%20F_1%20%2B%20F_2%5C%5C%5C%5CF_2%20%3D%20F%20-%20F_1%5C%5C%5C%5CF_2%20%3D%20420%20%5C%20N%20-%20140%20%5C%20N%5C%5C%5C%5CF_2%20%3D%20280%20%5C%20N)
![F_2 = 280 \ East](https://tex.z-dn.net/?f=F_2%20%3D%20280%20%5C%20East)
(b) When the resultant force is pointing along west line
the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.
![F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N](https://tex.z-dn.net/?f=F%20%3D%20F_2%20-%20F_1%5C%5C%5C%5CF_2%20%3D%20F%20%2B%20F_1%5C%5C%5C%5CF_2%20%3D%20420%20%5C%20N%20%2B%20140%20%5C%20N%5C%5C%5C%5CF_2%20%3D%20560%20%5C%20N)
![F_2 = 560 \ West](https://tex.z-dn.net/?f=F_2%20%3D%20560%20%5C%20West)
This is a problem based on the logic and interpretation of the variables. From the measured data taken
what is collected by the two individuals is expressed as,
- NED reference system: (x, t)
- PAM reference system: (x ', t')
From the reference system we know that ν is the speed of PAM (the other reference system) as a measurement by NED.
Then ν' is the speed of NED (from the other system of the reference) as a measurement by PAM.
Answer:
11300 kgm3
Hope this helps
The electric potential energy of the pair of charges when the second charge is at point b is U at b = +7.3×10⁻⁸J.
Electric potential is the amount of work done in moving point charge from infinity to aspecific point.
Calculation of the electric potential energy:
Here the particle should be moved from the point at the time when the potential energy should be U a
The U b should be the change in the potential energy
W is work done.
(W at a )-(W at b) = U a - U b
U b = U a - (W at a )+(W at b)
So,
= 5.4 × 10⁻⁸J - ( -1.9×10⁻⁸ J)
= +7.3×10⁻⁸J.
Learn more about electric potential here:
brainly.com/question/24284560
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Answer: C. physical fitness components
Explanation:
The physical activities includes daily activities which are part of daily routine. These include exercise, cooking, walking and others.
The physical fitness components can reduce the risk of beginning of the diseases and they will promote total health. These include cardiovascular endurance which provide safety against the heart diseases, muscular strength will allow the body to perform daily activities without any difficulties, flexibility, and body composition. The body composition will help to keep the body in proper shape.