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monitta
3 years ago
7

Help me, please!!!

Physics
2 answers:
disa [49]3 years ago
7 0
Divide 764 by 500 it should give you the answee
Rashid [163]3 years ago
5 0
Simple. Divide 500 by 764 to get 0.654 HP. 
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How does the work needed to lift an object and the gravitational potential energy of an object compare
Ganezh [65]

When you do work to lift the object, the amount of work you do BECOMES the object's gravitational potential energy.  It GETS its potential energy from the work you do to lift it.  They're equal.  You lose it, and the object gains it.  Energy is not created or destroyed.  It's just transferred from you to the object.  

Later, when you DROP the object, GRAVITY does the same amount of work on it, to pull it to the ground.  Again, no energy is created or destroyed.  Every time a force acts to move anything, the energy to do it comes from somewhere, and the energy goes somewhere.

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3 years ago
Paola conducts an investigation to determine how temperature affects plant growth. Each plant started at the same height, receiv
professor190 [17]

Answer:

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3 years ago
A moving walkway at the airport moves a 120Kg person 35m in 150s. How much power did this require?
Alexxx [7]

The amount of power required to move the 120 Kg person to a distance of 35 m in 150 s is 274.4 W

<h3>How to determin the power</h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = force (F) × distance (d)

Therefore,

P = Fd / t

With the above formula, we can obtain the power as follow:

  • Mass (m) = 120 Kg
  • Distance (d) = 35 m
  • Time (t) = 150 s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Force (F) = mg = 120 × 9.8 = 1176 N
  • Power (P) = ?

P = Fd / t

P = (1176 × 35) / 150

P = 41160 / 150

P = 274.4 W

Thus, the power is 274.4 W

Learn more about power:

brainly.com/question/20353916

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6 0
1 year ago
Not a question but need a lot of tips
skad [1K]

DibujaZos da buenos tips e incluso el pinta con colores faber castel son económicos y el dibujo queda epico

8 0
3 years ago
Given that the CFL bulb is rated at 10% efficiency, if the LED bulb consumes half the amount of electrical power, for the same a
Butoxors [25]

Answer and explanation:

The efficiency of the LED bulb is 20% while The efficiency of the Inc bulb is 1%.

The lightbulb efficiency can be defined as the quotient between the amount of usable light and the amount of electrical power output. For the efficiency of the CFL Bulb:

\epsilon_{CFL}=\frac{L_0}{P_0}=0.1

Therefore:

\epsilon_{led}=\frac{L_0}{0.5P_0}=2 \cdot0.1=0.2\\\epsilon_{INC}=\frac{L_0}{10P_0}=0.1 \cdot 0.1=0.01

4 0
3 years ago
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