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1 year ago

There are several ways to model a compound one type of model is shown ?what is the chemical formula for the molecule modeled?

Physics

1 answer:

s2008m [1.1K]1 year ago

7 0

The is organic compound with the correct chemical formula C4H9O2.

<h3>What is a model?</h3>

A model is a representation of reality. A model serves the purpose of prediction as well as explanation.

Looking at the model of the molecule we can see that it is the organic compound with the correct chemical formula C4H9O2. The molecule is shown in the image attached to this answer.

Missing parts:

There are several ways to model a compound. One type of model is shown.

What is the chemical formula for the molecule represented by the model?

CHO

C4H9O2

C4H8O

C3H8O2

Learn more about molecular models:brainly.com/question/156574?

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At 9:13AM a car is traveling at 35 miles per hour. Two minutes later, the car istraveling at 85 miles per hour. Prove that are s

andreyandreev [35.5K]

Answer:

There is at least one instant which instantaneous acceleration is equal to average acceleration. $a = 1500\,\frac{km}{h^{2}}$ .

Explanation:

The average acceleration experimented by the car is:

$\bar a = \frac{85\,\frac{km}{h} - 35\,\frac{km}{h} }{\frac{2}{60}\,h }$

$\bar a = 1500\,\frac{km}{h^{2}}$

According to the Rolle's Theorem, there is at least one instant t so that instantaneous acceleration equal to average acceleration for the analyzed interval. That is to say:

$v'(c) = \frac{v(\frac{2}{60} )-v(0)}{\frac{2}{60}-0}$

If car is accelerating at constant rate, instantaneous acceleration coincides with average acceleration for all instant t. Then, instantaneous acceleration is:

$a = 1500\,\frac{km}{h^{2}}$

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2 years ago

Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its

antoniya [11.8K]

A) Moment of inertia about an axis passing through the point where the two segments meet : $I_A=\frac{1}{12} M L^2$

B) Moment of inertia passing through the point where the midpoint of the line connects to its two ends: $I x=\frac{1}{3} M L^2$

What is Moment of inertia?

The term "moment of inertia" refers to a physical quantity that quantifies a body's resistance to having its speed of rotation along an axis changed by the application of a torque (turning force). The axis might be internal or exterior, fixed or not.

A) The moment of inertia about an axis passing through the point where the two segments meet is $I_A=\frac{1}{12} M L^2$ given that the rod is bent at the center and distance from all the points to the axis remains the same, the moment of inertia about the center will remain the same.

B) Determine the moment of inertia about an axis passing through the point midpoint of the line which connects the two ends

First step: determine the distance between the ends ( d )

After applying Pythagoras theorem $\mathrm{d}=\frac{\sqrt{2}}{2} L$

Next step : determine distance between the two axis $(\mathrm{x})$

After applying Pythagoras theorem

$\mathrm{x}=\frac{\sqrt{2}}{4} L$$$

Final step : Calculate the value of $\mathrm{I}_{\mathrm{x}}$

applying Parallel Axis Theorem

$I_x=I_8+M x^2$

$\begin{aligned}& =\frac{1}{12} M L^2+\frac{1}{4} M L^2 \\& \therefore \quad I x=\frac{1}{3} M L^2 \\&\end{aligned}$

Hence we can conclude that Moment of inertia about an axis passing through the point where the two segments meet: $I_A=\frac{1}{12} M L^2$ , Moment of inertia passing through the point where the midpoint of the line connects its two ends: $I x=\frac{1}{3} M L^2$

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5 0

5 months ago

A vector always consits of

Kazeer [188]

Answer:

Size and Direction

Explanation:

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2 years ago

What is the magnitude of the force a charge 25uc exerts on a charge 3mc 35 cm away?

Misha Larkins [42]

5.51 × 10 power 12 newton is answer

3 0

2 years ago

Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez

katrin [286]

Answer:

a= 4.4×10 m/s^2

Explanation:

pressure P = E/c

Where, E = 100 W/m^2 intensity of light

c= speed of light = 3×10^8 m/s

P = 1000/ 3×10^8

P = 3.33×10^(-6) Pa

Force F = P×A

P is the pressure and c= speed of light

F = 3.33×10^{-6}×6.65×10(-29)

= 2.22×10^{-6}

acceleration a = F/m = 2.22×10^{-6}/ 5.10×10^{-27}

a= 4.4×10 m/s^2

4 0

2 years ago