Answer:
Option B seems to be the appropriate choice,
Explanation:
The given question is incomplete. Please find the attachment of the complete question.
- From either the principle or law of the Coulombs, there would have been either pressure (force) through attachment or repulsion amongst charges.
- It is evident from the analysis presented that perhaps the bee becomes positively (+) charged and would have been drawn either by negatively (-) charged roots of the plants or stem.
As a consequence, the vegetation is electric current polarized because as activated bee pursued.
Answer:
91.64 km
91.64 km high material would go on earth if it were ejected with the same speed as on Io.
Explanation:
According to Newton Law of gravitation:
![g=\frac{Gm}{r^2}](https://tex.z-dn.net/?f=g%3D%5Cfrac%7BGm%7D%7Br%5E2%7D)
Where:
G is gravitational constant=![6.67*10^{-11} m^3/kg.s^2](https://tex.z-dn.net/?f=6.67%2A10%5E%7B-11%7D%20m%5E3%2Fkg.s%5E2)
For Moon lo g is:
![g_M=\frac{6.67*10^{-11}*8.93*10^{22}}{(1821*10^3)^2m^2} \\g_M=1.7962 m/s^2](https://tex.z-dn.net/?f=g_M%3D%5Cfrac%7B6.67%2A10%5E%7B-11%7D%2A8.93%2A10%5E%7B22%7D%7D%7B%281821%2A10%5E3%29%5E2m%5E2%7D%20%5C%5Cg_M%3D1.7962%20m%2Fs%5E2)
According to law of conservation of energy
Initial Energy=Final Energy
![K.E_i+mgh_i=K.E_f+mgh_f](https://tex.z-dn.net/?f=K.E_i%2Bmgh_i%3DK.E_f%2Bmgh_f)
![\frac{1}{2}m(v_0)^2+mgh_o= \frac{1}{2}m(v_f)^2+mgh_f\\At\ maximum\ height\ v_f=0\\\frac{1}{2}m(v_0)^2+0=mgh_f\\v_0=\sqrt{2gh_f}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dm%28v_0%29%5E2%2Bmgh_o%3D%20%5Cfrac%7B1%7D%7B2%7Dm%28v_f%29%5E2%2Bmgh_f%5C%5CAt%5C%20maximum%5C%20height%5C%20v_f%3D0%5C%5C%5Cfrac%7B1%7D%7B2%7Dm%28v_0%29%5E2%2B0%3Dmgh_f%5C%5Cv_0%3D%5Csqrt%7B2gh_f%7D)
For Jupiter's moon Io:
Velocity is given by:
![v_0_M=\sqrt{2g_Mh_f_M}](https://tex.z-dn.net/?f=v_0_M%3D%5Csqrt%7B2g_Mh_f_M%7D)
For Earth Velocity is given by:
![v_0_E=\sqrt{2g_Eh_f_E}](https://tex.z-dn.net/?f=v_0_E%3D%5Csqrt%7B2g_Eh_f_E%7D)
Now:
![v_o_M=v_o_E](https://tex.z-dn.net/?f=v_o_M%3Dv_o_E)
![\sqrt{2g_Mh_f_M}=\sqrt{2g_Eh_f_E}\\h_f_E=\frac{g_Mh_f_M}{g_E}](https://tex.z-dn.net/?f=%5Csqrt%7B2g_Mh_f_M%7D%3D%5Csqrt%7B2g_Eh_f_E%7D%5C%5Ch_f_E%3D%5Cfrac%7Bg_Mh_f_M%7D%7Bg_E%7D)
![g_E=9.8 m/s^2](https://tex.z-dn.net/?f=g_E%3D9.8%20m%2Fs%5E2)
![g_m=1.7962 m/s^2, As\ Calculated\ above](https://tex.z-dn.net/?f=g_m%3D1.7962%20m%2Fs%5E2%2C%20As%5C%20Calculated%5C%20above)
![h_f_E=\frac{1.7962*500*10^3m}{9.8} \\h_f_E=91642.85 m\\h_f_E=91.64Km](https://tex.z-dn.net/?f=h_f_E%3D%5Cfrac%7B1.7962%2A500%2A10%5E3m%7D%7B9.8%7D%20%5C%5Ch_f_E%3D91642.85%20m%5C%5Ch_f_E%3D91.64Km)
91.64 km high material would go on earth if it were ejected with the same speed as on Io.
Answer:
197.263157895 m/s
169.491525424 m/s
Explanation:
x Denotes position
t Denotes time
Average velocity is given by
![v_a=\dfrac{x_2-x_1}{t_2}\\\Rightarrow v_a=\dfrac{1000-63}{4.75}\\\Rightarrow v_a=197.263157895\ m/s](https://tex.z-dn.net/?f=v_a%3D%5Cdfrac%7Bx_2-x_1%7D%7Bt_2%7D%5C%5C%5CRightarrow%20v_a%3D%5Cdfrac%7B1000-63%7D%7B4.75%7D%5C%5C%5CRightarrow%20v_a%3D197.263157895%5C%20m%2Fs)
The average velocity is 197.263157895 m/s
![v_a=\dfrac{x_2-x_1}{t_2}\\\Rightarrow v_a=\dfrac{1000-0}{5.9}\\\Rightarrow v_a=169.491525424\ m/s](https://tex.z-dn.net/?f=v_a%3D%5Cdfrac%7Bx_2-x_1%7D%7Bt_2%7D%5C%5C%5CRightarrow%20v_a%3D%5Cdfrac%7B1000-0%7D%7B5.9%7D%5C%5C%5CRightarrow%20v_a%3D169.491525424%5C%20m%2Fs)
The average velocity is 169.491525424 m/s
A high quality insecticide applied all along the axis and the surrounding area can protect against a recurrence for a substantial period of time.