<h3>
Answer:</h3>
Li₂S(aq)+Pb(NO₃)₂(aq)
→ PbS(s) + LiNO₃(aq)
K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)
<h3>
Explanation:</h3>
- According to solubility rules, metal sulfides are insoluble except Calcium sulfide(CaS), Magnesium sulfide(MgS), Barium sulfide(BaS), and those of potassium, sodium, and ammonium.
- Therefore, when all the other sulfides are formed during a reaction they form a precipitate that is shown to be in solid-state.
- Precipitates are formed during precipitation reactions when cations and anions combine to form a compound that is insoluble in water.
In our case; In the equations given, some reactions will take place to form a precipitate while others will not occur.
That is;
- Na₂S(aq)+KCl(aq) → No reaction
- Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)
- Pb(ClO₃)₂(aq)+NaNO₃(aq) → No reaction
- AgNO₃(aq)+KCl(aq) →AgCl(s) + KNO₃(aq)
- K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)
The first reaction will not occur.
The second equation is a precipitation reaction that forms lead(ii)sulfide which is a black precipitate.
The third reaction will not take place.
The fourth reaction will be a precipitation reaction forming silver chloride precipitate.
The fifth equation is also a precipitation reaction that forms tin(ii) sulfide, SnS which is a black precipitate.
Therefore; the equations that answers our question are;
- Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)
- K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)
<h2>
An acidic solution has > </h2>
Explanation:
pH is the negative logarithm of hydronium ion concentration present in a solution.
If the solution has high hydrogen ion concentration, then the pH will be low and the solution will be acidic. The pH range of acidic solution is 0 to 6.9. The solution has more than
If the solution has low hydrogen ion concentration, then the pH will be high and the solution will be basic. The pH range of basic solution is 7.1 to 14. The solution has more than
The solution having pH equal to 7 is termed as neutral solution.The solution has equal concentration of and
Learn more about acidic, basic and neutral solution
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d is the answer. according to me